What is a quartic function whose only real zeros are the following x=-3 and x=2
2 answers:
Answer:
x^2+x-6[/tex]
Explanation:
We have been given two zeroes x= -3 and x=2 of some quadratic equation
We have to find the quadratic equation when x=-3 is a zero means (x+3) is a factor and when x=2 is a zero means (x-2) is a factor
We have a formula to find the quadratic equation from zeroes is
Here sum of zero is -3+2=-1
And product of zero is (-3)(2)=-6
substituting the values in the formula we will get
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Work shown above! Answer is
a = 5 b = -2 c = 0
a = 5 b = -2 c = 0
To solve this, you need to isolate/get the variable "x" by itself in the inequality:
2(1 - x) > 2x Divide 2 on both sides
1 - x > x Add x on both sides to get "x" on one side of the inequality
1 - x + x > x + x
1 > 2x Divide 2 on both sides to get "x" by itself
or
(x is any number less than 1/2)
[Another way you could've solved it]
2(1 - x) > 2x Distribute 2 into (1 - x)
(2)1 + (2)(-x) > 2x
2 - 2x > 2x Add 2x on both sides
2 - 2x + 2x > 2x + 2x
2 > 4x Divide 4 on both sides to get "x" by itself