Question

What is a quartic function whose only real zeros are the following x=-3 and x=2

Answer 1

Because the zeros are -3 and 2, the factors are (x+3)(x-2)
expand it: x^2+3x-2x-6= x^2+x-6

Answer 2

Answer:

x^2+x-6[/tex]

Explanation:

We have been given two zeroes  x= -3 and x=2 of some quadratic equation

We have to find the quadratic equation when x=-3 is a zero means (x+3) is a factor and when x=2 is a zero means (x-2) is a factor

We have a formula to find the quadratic equation from zeroes is

$x^2-(sum of zeroes )x+product of zeroes$

Here sum of zero is -3+2=-1

And product of zero is (-3)(2)=-6

substituting the values in the formula we will get

$x^2 -(-x)+(-6)=x^2+x-6$