Question

What is the remainder when the polynomial 8x^2+4x−3 is divided by 2x−1?

Answer 1

The remainder of this polynomial is 1. 

Answer 2

Answer:

1

Step-by-step explanation:

Given: A polynomial $8x^{2} +4x-3$ is divided by another polynomial $2x-1$

To find: Remainder when $8x^{2} +4x-3$  is divided by $2x-1$

Solution:

To find the remainder when $8x^{2} +4x-3$  is divided by $2x-1$

First, equate $2x-1$ with 0.

Now, $2x-1=0$

$\implies2x=1$

$\implies x=\frac{1}{2}$

Now, to find the remainder put $x=\frac{1}{2}$ in $8x^{2} +4x-3$

So, we have

$8\times(\frac{1}{2})^{2}+4(\frac{1}{2} )-3$

$=8\times\frac{1}{4} +2-3$

$=2+2-3$

$=4-3$

$=1$

Hence, the remainder is 1.