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4 years ago

13

An elephant at an animal sanctuary weighs 5.5 tons. He receives a daily nutritional supplement. The instructions say to give 1 f

luid ounce of supplement for every 250 pounds of body weight. How many fluid ounces of supplement should the elephant receive?

2 answers:

Kobotan [32]4 years ago

4 0

Answer:

Step-by-step explanation:

IDK either i made the same answer yaknow?

Mademuasel [1]4 years ago

3 0

Answer:

The answer should be 44

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Is 32,643 divisible by both 3 and 9?

Oksi-84 [34.3K]

32,643/3=10,881 YES IT IS DIVISIBLE
32,643/9=3,627 YES IT IS DIVISIBLE

8 0

3 years ago

Read 2 more answers

Help please need those answers

icang [17]

We know: The sum of the measures of the angles of a triangle is equal 180°.

We have: m∠A =65°, m∠B = (3x - 10)° and m∠C = (2x)°.

The equation:

65 + (3x - 10) + 2x = 180

(3x + 2x) + (65 - 10) = 180

5x + 55 = 180 <em>subtract 55 from both sides</em>

5x = 125 <em>divide both sides by 5</em>

x = 25

m∠B = (3x - 10)° → m∠B = (3 · 25 - 10)° = (75 - 10)° = 65°

m∠C = (2x)° → m∠C = (2 · 25)° = 50°

<h3>Answer: x = 25, m∠B = 65°, m∠C = 50°</h3>

8 0

3 years ago

Simplify the following expression as much as you can use exponential properties. (6^-2)(3^-3)(3*6)^4

gtnhenbr [62]

Answer:

Simplifying the expression $(6^{-2})(3^{-3})(3*6)^4$ we get $\mathbf{108}$

Step-by-step explanation:

We need to simplify the expression $(6^{-2})(3^{-3})(3*6)^4$

Solving:

$(6^{-2})(3^{-3})(3*6)^4$

Applying exponent rule: $a^{-m}=\frac{1}{a^m}$

$=\frac{1}{(6^{2})}\frac{1}{(3^{3})}(18)^4\\=\frac{(18)^4}{6^{2}\:.\:3^{3}} \\$

Factors of $18=2\times 3\times 3=2\times3^2$

Factors of $6=2\times 3$

Replacing terms with factors

$=\frac{(2\times3^2)^4}{(2\times 3)^{2}\:.\:3^{3}} \\=\frac{(2)^4\times(3^2)^4}{(2)^2\times (3)^{2}\:.\:3^{3}} \\$

Using exponent rule: $(a^m)^n=a^{m\times n}$

$=\frac{(2)^4\times(3)^8}{(2)^2\times (3)^{2}\:.\:3^{3}} \\=\frac{2^4\times 3^8}{2^2\times 3^{2}\:.\:3^{3}}$

Using exponent rule: $a^m.a^n=a^{m+n}$

$=\frac{2^4\times 3^8}{2^2\times 3^{2+3}}\\=\frac{2^4\times 3^8}{2^2\times 3^{5}}$

Now using exponent rule: $\frac{a^m}{a^n}=a^{m-n}$

$=2^{4-2}\times 3^{8-5}\\=2^{2}\times 3^{3}\\=4\times 27\\=108$

So, simplifying the expression $(6^{-2})(3^{-3})(3*6)^4$ we get $\mathbf{108}$

7 0

3 years ago

Please help me with this question

Dmitrij [34]

Answer:

a) number 2 and 3 appeared a minimum number of times

b) number 5 appeared a maximum number of times

c) number 1, 4 and 6 appear an equal number of times (4 times). Also number 2 and 3 appear an equal number of times (1 time)

d) Even numbers turned up 9 times. The even numbers in a dice are 2 4 and 6. Add up how many times they came up: 1+4+4=9

f) Odd numbers turned up 11 times. The odd numbers in a dice are 1, 3 and 5. Add up how many times they came up: 4+1+6=11

7 0

3 years ago

The line is given by equation y–1.5x = c. What is the value of c if the line passes through the point K (2, –3).

aleksandr82 [10.1K]

Answer:

c = -6

Step-by-step explanation:

To find the value of c to make the line pass through the point K = (2, -3), we just need to use the values of x = 2 and y = -3 in the equation, then we find the value of c.

So, we have that:

y - 1.5*x = c

(-3) - 1.5 * (2) = c

-3 - 3 = c

c = -6

So the value of c is -6

To check if the value is correct, we can use the value x = 2 and see if the value of y is -3:

y - 1.5*x = -6

y - 1.5*2 = -6

y - 3 = -6

y = -6 + 3 = -3

So it's correct.

7 0

3 years ago

Read 2 more answers