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levacccp [35]
3 years ago
11

Math question, help please.

Mathematics
2 answers:
tekilochka [14]3 years ago
5 0

Answer: EB = 20

Step-by-step explanation:

Hi there. I'm sending you a picture of how the triangle looks like with the sides identified by their values. Given that AB | DE, meaning that they are proportional, then we can assume this:

- AD | EB

- CD | CE

We can also set this ratio up:

\frac{15}{EB} = \frac{21}{28}

Cross multiply the proportion and then divide, to find the value of EB:

15 * 28 / 21=20

Side EB should be equal to 20.

galben [10]3 years ago
3 0

Answer:

EB =20

Step-by-step explanation:

CD : DA = CE : EB

21 : 15 = 28 : EB

21*EB = 28*15

EB = 28*15/21 = 20

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Answer:

D) 134°

Step-by-step explanation:

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a combination of two rigid transformations on a preimage will always/ sometimes/never produce the same image when taken in a dif
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If you apply two translations, then order doesn't matter. However, if you apply a translation and a rotation, then the order will matter because you'll be able to get two different image outputs. So it depends on what the transformations are.

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PLEASE HELP! A) 2.9 B) 9.2 C) 3.3 D) 5
Eva8 [605]

Answer:

9.2 =x

Step-by-step explanation:

Since this is a right triangle, we can use trig functions

tan theta = opp/ adj

tan 57 = x/6

6 tan 57 = x

9.239189783 = x

9.2 =x

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3 years ago
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Call an integer $n$ oddly powerful if there exist positive integers $a$ and $b$, where $b>1$, $b$ is odd, and $a^b = n$. How
azamat

Answer:

There are 16 oddly powerful integers less than 2010

Step-by-step explanation:

∵ b is an odd integer

∵ b > 1

∴ The first value of b is 3

∵ a is an integer

- We can use a = 1, 2, 3, ..........

∵ a^{b}=n

∵ n < 2010

- Let a = 1, 2, ............... 12 because 12³ is greatest integer  < 2010

∵ 1³ = 1, 2³ = 8, 3³ = 27, 4³ = 64, 5³ = 125, 6³ = 216, 7³ = 343,

   8³ = 512, 9³ = 729, 10³ = 1000, 11³ = 1331, 12³ = 1728

∴ There are 12 oddly powerful integers with b = 3

Now the second value of b is 5

1^{5}=1 but we took 1 before so we will start with 2

∵ 2^{5}=32, 3^{5}=243, 4^{5}=1024

- 4^{5} is the greatest integer < 2010

∴ There are 3 oddly powerful integers with b = 5

Now the third value of b is 7

∵ 2^{7}=128

- 2^{7} is the greatest integer < 2010

∴ There is 1 oddly powerful integers with b = 7

Now the fourth value of b is 9

∵ 2^{9}=512

- 2^{9} is the greatest integer < 2010

- But we used 512 before

∴ There is no oddly powerful integers with b = 9

- 9 is the greatest value of b which makes a^{b}

∵ 12 + 3 + 1 = 16

∴ There are 16 oddly powerful integers less than 2010

5 0
3 years ago
A 440.0-volt electric heater draws 10.0 amperes of current. according to Ohms law,what is the resistenace of the heater
Zanzabum

Answer:

The resistance of the heater is 44 ohms.

Step-by-step explanation:

Given that,

Voltage of electric heater, V = 440 volts

Current drawn by the heater, I = 10 A

We need to find the resistance of the heater. It is a case of Ohm's law. Its mathematical form is given by :

V=IR

R is resistance of the heater

R=\dfrac{V}{I}\\\\R=\dfrac{440\ V}{10\ A}\\\\R=44\ \Omega

So, the resistance of the heater is 44 ohms. Hence, this is the required solution.

4 0
3 years ago
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