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Scorpion4ik [409]
3 years ago
6

PLS HURRRRRRRYYYYY TYYY

Mathematics
1 answer:
Ede4ka [16]3 years ago
8 0

Answer:

It's 15.70796. Won't go in-depth since time seems to be of the essence

Step-by-step explanation:

Won't go in-depth since time seems to be of the essence

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a window is shaped like a parallelogram. the height of the window is half the length of the base of the window. the base of the
rusak2 [61]

The area of the parallelogram is 36 inches square.

We have a parallelogram shaped window whose dimensions are as follows-

base (b) : 12 inches

height (h) : \frac{1}{2} \times 12 = 6 inches

Other side = 10 inches

We have to find the area of the window.

<h3>What is the formula to calculate the area of a parallelogram of given base (b) and height (h).</h3>

The area of the parallelogram is given by -

A = \frac{1}{2} \times base\times height

In the question given - We can apply the above formula to estimate the area of the window.

A = \frac{1}{2} \times 12\times6 = 36 inches square.

Hence, the area of the parallelogram is 36 inches square.

To solve more questions on Parallelograms, visit the link below-

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2 years ago
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Plot square root of 6 on the number line.
nasty-shy [4]

It is located at 2.45, almost exactly the middle

6 0
3 years ago
Name the type of symmetry for the figure.
tangare [24]
I'm pretty sure it's B. rotational
6 0
4 years ago
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Help me please this is 7th grade math
kodGreya [7K]

Answer:

A = 113. 097

Step-by-step explanation:

A = πr^2

A = π6^2

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8 0
4 years ago
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How do I calculate this? Is there a formula?
alex41 [277]

<u>Answer:</u>

Height of cables = 23.75 meters

<u>Step-by-step explanation:</u>

We are given that the road is suspended from twin towers whose cables are parabolic in shape.

For this situation, imagine a graph where the x-axis represent the road surface and the point (0,0) represents the point that is on the road surface midway between the two towers.

Then draw a parabola having vertex at (0,0) and curving upwards on either side of the vertex at a distance of x = 600 or x = -600, and y at 95.

We know that the equation of a parabola is in the form y=ax^2 and here it passes through the point (600, 95).

y=ax^2

95=a \times 600^2

a=\frac{95}{360000}

a=\frac{19}{72000}

So new equation for parabola would be y=\frac{19x^2}{72000}.

Now we have to find the height (y)of the cable when x= 300.

y=\frac{19 (300)^2}{72000}

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