The setup boxes in the synthetic division are (b)
<h3>How to determine the setup boxes?</h3>
The dividend is given as:
x^3 + 4x^2 + x - 6
The divisor is given as:
x - 2
Set the divisor to 0
x - 2 = 0
Solve for x
x = 2
Remove the variables in the dividend
1 + 4 + 1 - 6
Remove the arithmetic signs
1 4 1 - 6
So, the setup is:
2 | 1 4 1 - 6
Hence, the setup boxes are (b)
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Step-by-step explanation:
You need to translate all the points to the right 3 and up 6
Therefore, you are going to use this formula:
(x,y) ⇾ (x + 3, y + 6)
This is the same format as the previous problem, if you have noticed.
Using this, plug in each coordinate, starting with P (5, -1)
(5, -1) ⇾ ( 5 + 3, -1 + 6)
(5, -1) ⇾ ( 8, 5 )
P = (8, 5)
Now point Q, (0, 8)
(0, 8) ⇾ (0 + 3, 8 + 6)
(0, 8) ⇾ ( 3, 14 )
Q = (3, 14)
And last but not least, the point R, (7, 5)
(7, 5) ⇾ (7 + 3, 5 + 6)
(7, 5) ⇾ ( 10, 11 )
R = (10, 11)
Therefore, P = (8, 5), Q = (3, 14), R = (10, 11) is your answer. This is the 4th option or D.
Hope this for you to understand this a bit more! =D
In order to solve this problem, we must solve an equation.
First, we need to define our unknown.
Let's call our number "n".
So, the sum of the number and 6 is the same as saying n+6
Then we need to multiply it by 2 (since it's twice the sum)
2(n+6)
This whole thing is equal to three times of the difference of the number and 8
n-8 is equal to the difference between the number and 8, then we need to multiply it by three.
3(n-8)
now, we set both sides equal and solve
The number is 36
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