All categories

3 years ago

81 is 18% of what number? Enter your answer in the box.

Mathematics

2 answers:

juin [17]3 years ago

5 0

81 is 18% of 450 you’re welcome

prohojiy [21]3 years ago

3 0

Answer:

450

Step-by-step explanation:

If 81 is 18% of a number then we can say that:

x × 0.18 = 81

We multiply by 0.18 because 18% is 0.18 as a decimal. So to work out the real number we divide 81 by 0.18:

81 ÷ 0.18 = 450

You might be interested in

A baseball team played 154 regular season games. The ratio of the number of games they won to the number of games they lost was

Fittoniya [83]

Answer:

88 won and 66 lost

Step-by-step explanation:

Won = $\frac{154}{4+3}$ ×4 = 88 games

Lost = 154 - 88 = 66 games

7 0

3 years ago

Find the area of the shape

Annette [7]

Answer:

36 + 36 = 72

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

.A variety of stores offer loyalty programs. Participating shoppers swipe a bar-coded tag at the register when checking out and

Leni [432]

Answer:

a) Null hypothesis: $\mu \leq 120$

Alternative hypothesis: $\mu > 120$

b) $t=\frac{130-120}{\frac{40}{\sqrt{80}}}=2.236$

The degrees of freedom are given by:

$df = n-1 = 80-1=79$

The p value for this case taking in count the alternative hypothesis would be:

$p_v =P(t_{79}>2.236)=0.0141$

Step-by-step explanation:

Information given

$\bar X=130$ represent the sample mean for the amount spent each shopper

$s=40$ represent the sample standard deviation

$n=80$ sample size

$\mu_o =120$ represent the value to verify

t would represent the statistic

$p_v$ represent the p value f

Part a

We want to verify if the shoppers participating in the loyalty program spent more on average than typical shoppers, the system of hypothesis would be:

Null hypothesis: $\mu \leq 120$

Alternative hypothesis: $\mu > 120$

The statistic for this case would be given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

Replacing the info given we got:

$t=\frac{130-120}{\frac{40}{\sqrt{80}}}=2.236$

The degrees of freedom are given by:

$df = n-1 = 80-1=79$

The p value for this case taking in count the alternative hypothesis would be:

$p_v =P(t_{79}>2.236)=0.0141$

5 0

3 years ago

A specimen of charcoal found at Stonehenge contains 63% as much Carbon-14 as a sample of present-day charcoal. What is the age o

seraphim [82]

Since we are given with the identity of the chemical as Carbon-14, we obtain the half-life of the chemical from a reliable source and get a value of 5730 years. The equation that we are going to use for this item is,
A(t)/A(0) = (0.50)^(n/5730)
where A(t) is the current amount, A(0) is the initial amount and n is the number of years. We know from the given that the ratio of A(t) and A(0) is equal to 0.63. Substituting this to the given,
0.63 = 0.50^(n/5730)
n = 3819.48
Thus, the sample is approximately 3819.5 years old.

5 0

3 years ago

I need help on a question

NeX [460]

Jb, this is the solution:

If T = (x + 3, y + 1),

T3 = 3(x + 3, y + 1)

T3 = 3x + 9, 3y + 3

The correct answer is C.

7 0

1 year ago