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3 years ago

Determine whether 3y = −7x + 8 is quadratic or not. Explain.

1 answer:

6 0

<span>C. No; there is no x^2-term, so a = 0.
For a function to be a quadratic it had to have an x raised to the second power. without it, this example is a linear equation.</span>

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What is the 15% of 800?

Murljashka [212]

Answer:

800(.15)= 120 is the solution

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3 years ago

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Question 7(Multiple Choice)

aalyn [17]

Answer:

C.) $log_2(\frac{x^3z^2}{y^4})$

Step-by-step explanation:

To find the answer, you need to simplify the expression. To do so, you must combine the logs. You can combine the logs because they all have the same subscript (2).

$3 log_2x - 4log_2y + 2log_2z$ <----- Given expression

$log_2x^3-log_2y^4+log_2z^2$ <----- Raise coefficients to variables

$log_2x^3+log_2z^2-log_2y^4$ <----- Rearrange

$log_2(x^3z^2)-log_2y^4$ <----- Multiply added logs

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1 year ago

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The given line segment has a midpoint at (−1, −2).

Sav [38]

As the midpoint is a point on the perpendicular line, we can solve by eliminating the other equations, like this:
Check if the point (-1,-2) is on the line y=-4x-4:
-4(-1)-4=0 is differente from -2.
-4(-1)-6=-2, so (-1,-2) is on the line y=-4x-6.
We check also for the other equation like this:
Third equation: (-1)-4 = -5 not equal to -2.
Fourth equation: (-1)-6=-7 not equal to -2.
So the correct answer is the line y=-4x-6

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3 years ago

If sine ⁡theta equals negative 8/17 and the terminal side of theta lies in quadrant IV, find cosine ⁡ theta .

Lelechka [254]

$\sin^2\theta+\cos^2\theta=1\implies \cos\theta=\pm\sqrt{1-\sin^2\theta}$

Since $\sin\theta=-\dfrac8{17}$ , it follows that

$\cos\theta=\pm\sqrt{1-\dfrac{64}{289}}=\pm\sqrt{\dfrac{225}{289}}=\pm\dfrac{15}{17}$

where the sign depends on the location of the terminal side of the angle. Since the terminal side lies in the fourth quadrant, that means the cosine of the angle is positive, so

$\cos\theta=\dfrac{15}{17}$

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3 years ago

Coordinates of England

adoni [48]

Answer:

52.3555 north

1.1745 west

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3 years ago