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3 years ago

13

To determine whether voters would be willing to vote for a tax increase to improve the city's parks, the park commission surveys

500 park users. Why is this sample likely to be biased?

1 answer:

Elodia [21]3 years ago

7 0

<span>Park users are too busy to be bothered with surveys.</span>

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Patty made a banner that has an area of 36 square inches,. The length and width of the banner are whole numbers. The length is 4

omeli [17]

Answer: width= 3 inches; length= 12 inches.

Step-by-step explanation:

From the question, the length is 4 times greater than the width.

Let the width of the banner be represented by y.

Since the length is 4 times greater than the width. It will be denoted as:

Length= 4 × y = 4y

Since area= length×width

4y × y = 36

4y^2 = 36

Divide both side by 4

y^2 = 36/4

y^2 = 9

We have to find the square root of 9

y= √9

y = 3

The width is 3 inches.

The length will be: (3×4) = 12 units.

3 0

3 years ago

Read 2 more answers

A bag contains white marbles and yellow marbles, 16 in total. The number of white marbles is 5 less than 2 times the number of y

bija089 [108]

Answer:

9 White marbles are present in the bag.

Step-by-step explanation:

Let the number of White marbles present in the bag be X and number of Yellow marbles present be Y .

Then according to the question ,

X + Y = 16 -(1) (As total marbles are 16)

Also,

X = 2Y - 5 -(2)

From Equation 1 , X = 16 - Y , Comparing with Equation 2 , we get,

16 - Y = 2Y - 5

3Y = 21.

Y = 7.

So, X = 16 - Y = 16 - 7 = 9.

Thus, 9 White marbles are present in the bag.

8 0

3 years ago

Mrs Prabhakar open a recurring deposit account of rupees 300 per month at 8% simple interest per annum on maturity he gets rupee

Goryan [66]

Step-by-step explanation:

300 x 8/100 x 1

=24

=(24+300)=324

=9930-324=9606

5 0

3 years ago

Find the nearest tenth of a degree

e-lub [12.9K]

Sin < O = 10/15 = 2/3
so m < O = 41.8 degrees

m < Y = 90 - 41.8 = 48.2 degrees

8 0

3 years ago

Complete the identity.<br> 1) sec^4 x + sec^2 x tan^2 x - 2 tan^4 x = ?

Alecsey [184]

Answer:

See Explanation

Step-by-step explanation:

<em>Question like this are better answered if there are list of options; However, I'll simplify as far as the expression can be simplified</em>

Given

$sec^4 x + sec^2 x tan^2 x - 2 tan^4 x$

Required

Simplify

$(sec^2 x)^2 + sec^2 x tan^2 x - 2 (tan^2 x)^2$

Represent $sec^2x$ with a

Represent $tan^2x$ with b

The expression becomes

$a^2 + ab- 2 b^2$

Factorize

$a^2 + 2ab -ab- 2 b^2$

$a(a + 2b) -b(a+ 2 b)$

$(a -b) (a+ 2 b)$

Recall that

$a = sec^2x$

$b = tan^2x$

The expression $(a -b) (a+ 2 b)$ becomes

$(sec^2x -tan^2x) (sec^2x+ 2 tan^2x)$

..............................................................................................................................

In trigonometry

$sec^2x =1 +tan^2x$

Subtract $tan^2x$ from both sides

$sec^2x - tan^2x =1 +tan^2x - tan^2x$

$sec^2x - tan^2x =1$

..............................................................................................................................

Substitute 1 for $sec^2x - tan^2x$ in $(sec^2x -tan^2x) (sec^2x+ 2 tan^2x)$

$(1) (sec^2x+ 2 tan^2x)$

Open Bracket

$sec^2x+ 2 tan^2x$ ------------------This is an equivalence

$(secx)^2+ 2 (tanx)^2$

Solving further;

................................................................................................................................

In trigonometry

$secx = \frac{1}{cosx}$

$tanx = \frac{sinx}{cosx}$

Substitute the expressions for secx and tanx

................................................................................................................................

$(secx)^2+ 2 (tanx)^2$ becomes

$(\frac{1}{cosx})^2+ 2 (\frac{sinx}{cosx})^2$

Open bracket

$\frac{1}{cos^2x}+ 2 (\frac{sin^2x}{cos^2x})$

$\frac{1}{cos^2x}+ \frac{2sin^2x}{cos^2x}$

Add Fraction

$\frac{1 + 2sin^2x}{cos^2x}$ ------------------------ This is another equivalence

................................................................................................................................

In trigonometry

$sin^2x + cos^2x= 1$

Make $sin^2x$ the subject of formula

$sin^2x= 1 - cos^2x$

................................................................................................................................

Substitute the expressions for $1 - cos^2x$ for $sin^2x$

$\frac{1 + 2(1 - cos^2x)}{cos^2x}$

Open bracket

$\frac{1 + 2 - 2cos^2x}{cos^2x}$

$\frac{3 - 2cos^2x}{cos^2x}$ ---------------------- This is another equivalence

8 0

3 years ago