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2 years ago

All of the following expressions simplify to -4x + 9, except

Mathematics

1 answer:

Alla [95]2 years ago

6 0

What are the options for the expressions?

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Mashcka [7]

To solve this we are going to use the formula for compounded interest: $A=P(1+ \frac{r}{n})^{nt}$
where
$A$ is the final amount after $t$ years
$P$ is the initial amount
$r$ is the interest rate in decimal form
$n$ is the number of times the interest is compounded per year
$t$ is the time in years

We know for our problem that $P=1380$ , $r= \frac{5}{100} =0.05$ , and $t=3$ . Since the interest is compounded daily, it is compounded 365 times in year; therefore, $n=365$ . Lets replace those values in our formula to find $A$ :
$A=P(1+ \frac{r}{n})^{nt}$
$A=1380(1+ \frac{0.05}{365})^{(365)(3)}$
$A=1603.31$

We can conclude the amount in Diane's after 3 years will be $1,603.31

4 0

3 years ago

Pleaseeeee help!!!!! Order them least to greatest please

Fiesta28 [93]

Answer and Step-by-step explanation:

$\pi$ is pi, or 3.14159

The absolute value of -4 ( |-4| ) is 4.

These numbers should go in this order:

-10 < 0.121212... < $\pi$ < |-4| < $5\frac{1}{2}$

Have a good day!

#teamtrees #PAW (Plant And Water)

8 0

2 years ago

Read 2 more answers

Solve 6 over x minus 3 equals 3 over x for x and determine if the solution is extraneous or not

Natali5045456 [20]

Answer:

x = 1

This is the equation that I interpreted:

6/(x) - 3 = 3/(x)

I have never worked with determining extraneous equations before, so I cannot answer the second part.

8 0

3 years ago

In the picture PLEASE HELP

Debora [2.8K]

I believe it's not a function because the input (x) 4 has two outputs(y), 2 and 8.

5 0

2 years ago

Find the directional derivative of f(x,y,z)=2z2x+y3f(x,y,z)=2z2x+y3 at the point (−1,4,3)(−1,4,3) in the direction of the vector

Feliz [49]

$f(x,y,z)=2z^2x+y^3$

$f$ has gradient

$\nabla f(x,y,z)=2z^2\,\vec\imath+3y^2\,\vec\jmath+4xz\,\vec k$

which at the point (-1, 4, 3) has a value of

$\nabla f(-1,4,3)=18\,\vec\imath+48\,\vec\jmath-12\,\vec k$

I'm not sure what the given direction vector is supposed to be, but my best guess is that it's intended to say $\vec u=15\,\vec\imath+25\,\vec\jmath$ , in which case we have

$\|\vec u\|=\sqrt{15^2+25^2}=5\sqrt{34}$

Then the derivative of $f$ at (-1, 4, 3) in the direction of $\vec u$ is

$D_{\vec u}f(-1,4,3)=\nabla f(-1,4,3)\cdot\dfrac{\vec u}{\|\vec u\|}=\boxed{\dfrac{294}{\sqrt{34}}}$

4 0

3 years ago