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AfilCa [17]
3 years ago
13

All of the following expressions simplify to -4x + 9, except

Mathematics
1 answer:
Alla [95]3 years ago
6 0
What are the options for the expressions?
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Rewrite the following expression using the properties of logarithms: log2z + 2log2z + 4log9y + 12log9x - 2log2y
Mashcka [7]

The rewritten form of the expression given in the task content in which case, the properties of the logarithm are used is; log2(z³/y²) + log9(y⁴x¹²).

<h3>What is the equivalent expression to the logarithmic expression given in the task content?</h3>

It follows from the task content that the logarithmic expression given in the task content is;

log2z + 2log2z + 4log9y + 12log9x - 2log2y

In which case, all terms are to their respective logarithmic bases.

Hence, it follows that; we have;

log2z³ - log2y² + log9y⁴ + log9x¹²

= log2(z³/y²) + log9(y⁴x¹²)

Read more on logarithm laws;

brainly.com/question/10208274

#SPJ1

4 0
2 years ago
HELP MEEEEEEEE<br> plsssssss
USPshnik [31]

Answer:

lol just found it.

Step-by-step explanation:

7 0
3 years ago
In which figure is point G an orthocenter?
PIT_PIT [208]

Answer:

The second/below one is where point G in an orthocenter

Step-by-step explanation:

3 0
2 years ago
HELP PLEASE ASAP..........
Usimov [2.4K]
Volume = l x w x h
180 = l (5 x 4)
180 = 20 l
6 = l

That means that the couch will fit, because the length of the van is 6 ft, which is also the length of the couch.
6 0
3 years ago
How many 10-digit ternary strings are there that contain exactly two 0s, three 1s, and five 2s?
Svet_ta [14]

There are \dbinom{10}2 ways of picking 2 of the 10 available positions for a 0. 8 positions remain.

There are \dbinom83 ways of picking 3 of the 8 available positions for a 1. 5 positions remain, but we're filling all of them with 2s, and there's \dbinom55=1 way of doing that.

So we have

\dbinom{10}2\dbinom83\dbinom55=\dfrac{10!}{2!(10-2)!}\dfrac{8!}{3!(8-3)!}\dfrac{5!}{5!(5-5)!}=2520

The last expression has a more compact form in terms of the so-called multinomial coefficient,

\dbinom{10}{2,3,5}=\dfrac{10!}{2!3!5!}=2520

5 0
2 years ago
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