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laiz [17]
3 years ago
12

Helppp plsssss!!! Show your work!!Thanks

Mathematics
1 answer:
ZanzabumX [31]3 years ago
6 0

First, determine if the boundary line should be dotted or solid. In this case, it should be dotted because the symbol is less than not less than or equal to. This leaves you with options B or D. Now, to see if it should be shaded up or down, test it by substituting any point, let's say the origin (0,0), to see if that point is a solution to the equation. If it is, you shade that side of the graph, but if it's not, you shade the other side of the graph.

0 is less than (-3/4)(0) + 2

0 is less than 2.

Because 0 is actually less than 2, the statement is correct and you shade below the line

Answer: D

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f⁻¹(x) = eˣ / 3

Step-by-step explanation:

f(x) = In(3x)

y = In(3x)

swap x and y: x = In(3y)

solve y: eˣ = 3y

y = eˣ / 3

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Verify the identity (tan x + 1)^2 + (tan x-1)^2= 2 sec^2 x
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(\tan x+1)^2+(\tan x-1)^2=2\sec^2x\\\\\text{use}\ \tan x=\dfrac{\sin x}{\cos x}\\\\L_s=\left(\dfrac{\sin x}{\cos x}+\dfrac{\cos x}{\cos x}\right)^2+\left(\dfrac{\sin x}{\cos x}-\dfrac{\cos x}{\cos x}\right)^2\\\\=\left(\dfrac{\sin x+\cos x}{\cos x}\right)^2+\left(\dfrac{\sin x-\cos x}{\cos x}\right)^2\\\\=\dfrac{(\sin x+\cos x)^2}{\cos^2x}+\dfrac{(\sin x-\cos x)^2}{\cos^2x}\\\\\text{use}\ (a\pm b)^2=a^2\pm2ab+b^2

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