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faust18 [17]
3 years ago
12

I can’t figure this out. Please help

Mathematics
2 answers:
patriot [66]3 years ago
7 0

Answer:

itjust algebra

Step-by-step explanation:

bulgar [2K]3 years ago
6 0

Answer:

\frac{3^{6} }{3^{4} }   or 3²

Step-by-step explanation:

Count the 3 and put it in the exhibitor for the numerator and the denominator of the fraction. You have \frac{3^{6} }{3^{4} } then put them in a line 3^{6}  3^{-4} = 3^{6-4} = 3^{2}

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The elevation of lake sam rayburn is 164 above mean sea level during the summer if it does not rain the elevation of the lake de
andrew-mc [135]

Answer:

I guess that you want to model the elevation of Lake Sam Rayburn.

During the summer, it is 165 ft above the sea level (the sea level is our position 0ft).

If it does not rain, the elevation of the lake decreases by 0.5ft each week.

So if we assume that there is no rain, we can write the elevation fo the lake as a linear relationship with slope equal to -0.5ft and y-intercept equal to 165ft.

L(w) = 165ft - 0.5ft*w

Where w is the number of weeks without rain, if we have 0 weeks without rain, then the level of the lake remains constant at 165ft above sea level,

L(0) = 165ft - 0.

4 0
4 years ago
I need clear steps to solve this. I am struggling with this part.
MissTica
In order to find the average of all the costs, first you need to add up all of the expenditures from each month. (ex. 1,084.45+886.40+968.45+1,117.60+995.80+1,379.86) After you find the solution from adding those numbers together, divide the solution by the amount of costs there are in order to find the average. Since it was for 6 months, get the total from the addition problem and divide it by 6 and that will be your answer.
8 0
3 years ago
What is the y-value when x equals - 12?
kirill115 [55]

Answer:

I think the answer is -140

7 0
3 years ago
1/2+1/5 using standard algorithm
scZoUnD [109]
1/2=5/10
1/5=2/10
1/2+1/5
=5/10+2/10
=7/10
So your answer is 7/10
8 0
4 years ago
Read 2 more answers
Can i get help plz in: <br> 12am=4 for a <br> and<br> -3x+2c=-3 for x <br> and<br> am=n+p for a
schepotkina [342]
For the first one) a = \frac{1}{3am}


For the second one) x = \frac{2c}{3} + 1


For the third one) a = \frac{n}{m} + \frac{p}{m}


Hope that helps, Good luck! (:
6 0
3 years ago
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