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2 years ago

Which equation represents a linear function that has a slope of g and a y-intercept of -6

Mathematics

1 answer:

KATRIN_1 [288]2 years ago

8 0

Answer:

Step-by-step explanation:

the slope of the line is the number that multiplies the x

the y intercept is the constant therm

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Solve for<br> 8 - 6r + 3 = 5

Oksanka [162]

Answer:

r = 1

Step-by-step explanation:

8 - 6r + 3 = 5

Combine like terms

11 - 6r = 5

Subtract 5 from both sides

6 - 6r = 0

Add 6r to both sides

6 = 6r

Divide both sides by 6

1 = r

5 0

2 years ago

Solve this equation 3(2x+3)=9

Scilla [17]

Answer:

Step-by-step explanation:

Isolate the variable x. First, distribute 3 to all terms within the parenthesis.

3(2x + 3) = 3(2x) + 3(3) = 6x + 9

6x + 9 = 9

Isolate the variable x. Note the equal sign, what you do to one side, you do to the other. First, subtract 9 from both sides.

6x + 9 (-9) = 9 (-9)

6x = 0

Divide 6 from both sides.

(6x)/6 = (0)/6

x = 0

0 is your answer.

3 0

2 years ago

Read 2 more answers

Solve this for fun! I already solved it, so you can give a simple answer.

Ivanshal [37]

is this 8th grade is it is it

4 0

3 years ago

Read 2 more answers

An aircraft manufacturer wants to determine the best selling price for a new airplane. The company estimates that the initial co

Blizzard [7]

Answer:

$(a)$ $C(x)=500+20x-5x^{\frac{3}{4}}+0.01x^2$

$p(x)=320-7.7p$

$R(x)=(320-7.7p)p=320p-7.7p^2$

$(b)$ $x=82 \text{planes}$

$(c)$ $p=\$30.91 M\;\; \text{per plane}$

$(d)$ maximum profit $=\$ 15.90M$

Step-by-step explanation:

Given that,

The company estimates that the initial cost of designing the aeroplane and setting up the factories in which to build it will be 500 million dollars.

The additional cost of manufacturing each plane can be modelled by the function.

$m(x)=20x-5x^{\frac{3}{4}}+0.01x^2$

$(a)$ Find the cost, demand (or price), and revenue functions.

$C(x)=500+20x-5x^{\frac{3}{4}}+0.01x^2$

$p(x)=320-7.7p$

$R(x)=(320-7.7p)p=320p-7.7p^2$

$(b)$ Find the production level that maximizes profit.

$f=R(x)-C(x)$

$\Rightarrow f=320p-7.7p^2-(500+20x-5x^{\frac{3}{4}}+0.01x^2)$

$\Rightarrow df=320dp-15.4pdp-20dx+5(\frac{3}{4} )x^{\frac{-1}{4} }dx-0.02xdx$

$x=320-7.7p$

$p=\frac{320-x}{7.7}$

$\frac{dp}{dx} = \frac{-1}{7.7}$

$\frac{df}{dx}=\frac{320}{-7.7} -\frac{15.4(320-x) }{7.7(\frac{-1}{7.7} )}-20+5\frac{3}{4} x^{\frac{-1}{4}} -0.02x=0$

$\Rightarrow -41.5584+83.1169-0.2597x-20+3.75x^{\frac{-1}{4} }-0.02x=0$

$\Rightarrow 21.5585+3.75x^{\frac{-1}{4} }-0.279x=0$

$\Rightarrow x=82 \text{planes}$

$(c)$ Find the associated selling price of the aircraft that maximizes profit.

$p=\frac{320-82}{7.7}$

$\Rightarrow p=\$30.91 M\;\; \text{per plane}$

$(d)$ Find the maximum profit.

Manufacturing cost of one plane is:

$m(1)=20-5+0.01$

$=\$15.01 M$

maximum profit $=\$(30.91-15.01)M$

$=\$15.90M$

3 0

2 years ago

Solve: 7.85 + q ≤ -18.15 *

Ilia_Sergeevich [38]

Answer:

q≤-26

Step-by-step explanation:

7.85+q≤-18.15

-7.85 -7.85

q≤-26

7 0

3 years ago