Tahmid has 96 figures, Sandeep has 1/3 of it so
96(1/3) = 96/3 = 32
Sandeep has 32 figures
Tahmid 96 ; Sandeep 32
How many must tahmid give so they have the same figures?
First take the difference of the two so we know how many tahmid can give.
96-32 = 64
now they each have 32 and 64 give or keep. for each one tahmid gives, he must keep one himself so to match the number they both own. so we divide the number of 2, one part to give, the other part to keep himself.
64/2 = 32
So, Tahmid must give Sandeep 32 figures to have equal number of figures of 64 each.
Answer:
The 1st and 4th statements are true.
Answer:
Step-by-step explanation:
The formula of a slope:
If
m > 0, then a line is rising
m < 0, then a line is falling
m = 0, then a line is horizontal
m is undefined, then a line is vertical
<h2>a.</h2>
(2, 1) and (4, 5)
<h2>b.</h2>
(-1, 0) and (3, -5)
<h2>c.</h2>
(2, 1) and (-3, 1)
<h2>d.</h2>
(-1, 2) and (-1, -5)
Answer:
16m tall
Step-by-step explanation:
Distance casted by the shadow = 32m = hypotenuse
Angle of elevation = 30 degrees
Required
Height of the building = opposite
Using the SOH CAH TOA identity
sin theta = opp/hyp
sin 30 = x/32
0.5 = x/32
x = 0.5 * 32
x = 16m
Hence the building is 16m tall
Answer:
Step-by-step explanation:
how does the graph look like
