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2 years ago

14

A wheel barrow can carry up to 300 pounds of weight. A bag of soil wieghs 20 pounds. Write and solve an inequality to respresent

the number of bags of soil the wheelbarrow can carry.

1 answer:

Alik [6]2 years ago

8 0

Let x= the number of bags of soil

20x(less than or equal to sign) 300

divide both sides by 20 and you get x is less than or equal to 15

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Which matrix represents the system of equations shown below<br> Plz help..<br> See picture

Furkat [3]

Basically

just put the coeficinets of each variable in the apropriate row

example
ax+by=c and
dx+ey=f

would go in like this
$\left[\begin{array}{ccc}a&b&|c\\d&e&|f\end{array}\right]$

so
3x+1=1 and
0x-1y=5

$\left[\begin{array}{ccc}3&1&|1\\0&-1&|5\end{array}\right]$

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4 0

3 years ago

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A restaurant manager states the number of customers that enter the restaurant is equal to 4 times the number of people that buy

yarga [219]

Answer:

26 customers

Step-by-step explanation:

Represent customers entering as y and those buying hot dogs as x

$y = 4x + 9$

$y = 3x + 35$

Required

Determine the number of people buying hotdogs (x)

Substitute 4x + 9 for y in the second equation

$4x + 9 = 3x + 35$

Collect Like Terms

$4x - 3x = 35 - 9$

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3 years ago

Ilia_Sergeevich [38]

Answer:

its will decrease by about 0.08% have a great day :)

Step-by-step explanation:

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3 years ago

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Please help!! Thank you if you do!!

expeople1 [14]

I think it is BD but I’m not 100% sure

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2 years ago

A college sends a survey to members of the class of 2012. Of the 1254 people who graduated that year, 672 are women, of whom 124

Svetllana [295]

Answer:

a) $P(F) = \frac{672}{1254}=\frac{112}{209}=0.536$

b) $P(M) = \frac{582}{1254}= \frac{97}{209}=0.464$

c) $P(A') = 1-P(A) = 1- \frac{124}{672}= \frac{137}{168}=0.815$

Step-by-step explanation:

For this case we have a total of 1254 people. 672 are women and 582 are female.

We know that 124 women wnat on to graduate school.

And 198 male want on to graduate school

We can define the following events:

F = The alumnus selected is female

M= The alumnus selected is male

A= Female and attend graduate school

And we can find the probabilities required using the empirical definition of probability like this:

Part a

$P(F) = \frac{672}{1254}=\frac{112}{209}=0.536$

Part b

$P(M) = \frac{582}{1254}= \frac{97}{209}=0.464$

Part c

For this case we find the probability for the event A: The student selected is female and did attend graduate school

$P(A) =\frac{124}{672}=\frac{31}{168}=0.185$

And using the complement rule we find P(A') representing the probability that the female selected did not attend graduate school like this:

$P(A') = 1-P(A) = 1- \frac{124}{672}= \frac{137}{168}=0.815$

4 0

3 years ago