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BigorU [14]
3 years ago
15

Solve the following equation using the quadratic formula.

Mathematics
2 answers:
abruzzese [7]3 years ago
6 0

Answer:

C. x= 4 + 9i or x = 4 - 9i

Step-by-step explanation:

x^2 - 8x + 97 = 0

Use the quadratic formula.

\frac{-b\pm \sqrt{b^2-4ac}}{2a}

Substitute a = 1, b = -8, and c = 97.

\frac{-\left(-8\right)\pm\sqrt{\left(-8\right)^2-4\times 1\times 97}}{2\times 1}

Evaluate.

\frac{8\pm\sqrt{324}i}{2\times 1}

\frac{8\pm18i}{2}

4\pm9i

konstantin123 [22]3 years ago
5 0

Answer:

x = 4   ±9i

Step-by-step explanation:

x^2 - 8x + 97 = 0

Complete the square by subtracting 97 from each side

x^2 - 8x =- 97

Take the coefficient of x

-8 and divide by 2

-8/2 = -4

Then square it

(-4)^2 = 16

Add it to each side

x^2 - 8x + 16 = -97+16

(x-4)^2 = -81

Take the square root of each side

x-4 = ±sqrt(-81)

x-4 = ±9i

Add 4 to each side

x = 4   ±9i

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Aaron’s mother purchases a new computer for $1750. If she claims a linear depreciation (loss of value) on the computer at a rate
kirill [66]

After 8 years the value of the computer to be $0 if the Aaron’s mother purchases a new computer for $1750.

<h3>What is a sequence?</h3>

It is defined as the systematic way of representing the data that follows a certain rule of arithmetic.

We have:

Aaron’s mother purchases a new computer for $1750. If she claims a linear depreciation (loss of value) on the computer at a rate of $250 per year.

The above problem can be solved using concept of arithmetic sequence

The starting value = $1750

After one year = 1750 - 250 = $1500

After second year = 1500 - 250 = $1250

Common difference = 1500 - 1750 = -250

a(n) = 1750 + (n - 1)(-250)

a(n) = 0  (final value is zero given)

0 = 1750 + (n - 1)(-250)

n - 1 = 7

n = 8 years

Thus, after 8 years the value of the computer to be $0 if the Aaron’s mother purchases a new computer for $1750.

Learn more about the sequence here:

brainly.com/question/21961097

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