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yarga [219]
3 years ago
8

BRAINLIESTT ASAP! PLEASE HELP ME :)

Mathematics
1 answer:
Anvisha [2.4K]3 years ago
3 0

Step-by-step explanation:

\displaystyle y = Asec(Bx - C) + D

According to this trigonometric function, −C gives you the OPPOSITE terms of what they really are, so be EXTREMELY CAREFUL:

\displaystyle Phase\:[Horisontal]\:Shift → \frac{0}{4} = 0 \\ Period → \frac{2}{4}π = \frac{π}{2}

Therefore we have our answer.

Extended Information on the trigonometric function

\displaystyle Vertical\:Shift → D \\ Phase\:[Horisontal]\:Shift → \frac{C}{B} \\ Period → \frac{2}{B}π \\ Amplitude → |A|

NOTE: Sometimes, your <em>vertical shift</em> might tell you to shift your graph below or above the <em>midline</em> where the amplitude is. Moreover, ALL <em>tangent</em>,<em> </em><em>secant</em>, <em>cosecant</em>, and <em>cotangent</em> functions have NO AMPLITUDE.

I am joyous to assist you anytime.

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In Exercises 45–48, let f(x) = (x - 2)2 + 1. Match the<br> function with its graph
MA_775_DIABLO [31]

Answer:

45) The function corresponds to graph A

46) The function corresponds to graph C

47) The function corresponds to graph B

48) The function corresponds to graph D

Step-by-step explanation:

We know that the function f(x) is:

f(x)=(x-2)^{2}+1

45)

The function g(x) is given by:

g(x)=f(x-1)

using f(x) we can find f(x-1)

g(x)=((x-1)-2)^{2}+1=(x-3)^{2}+1

If we take the derivative and equal to zero we will find the minimum value of the parabolla (x,y) and then find the correct graph.

g(x)'=2(x-3)

2(x-3)=0

x=3

Puting it on g(x) we will get y value.

y=g(3)=(3-3)^{2}+1

y=g(3)=1

<u>Then, the minimum point of this function is (3,1) and it corresponds to (A)</u>

46)

Let's use the same method here.

g(x)=f(x+2)

g(x)=((x+2)-2)^{2}+1

g(x)=(x)^{2}+1

Let's find the first derivative and equal to zero to find x and y minimum value.

g'(x)=2x

0=2x

x=0

Evaluatinf g(x) at this value of x we have:

g(0)=(x)^{2}+1

g(0)=1

<u>Then, the minimum point of this function is (0,1) and it corresponds to (C)</u>

47)

Let's use the same method here.

g(x)=f(x)+2

g(x)=(x-2)^{2}+1+2

g(x)=(x-2)^{2}+3

Let's find the first derivative and equal to zero to find x and y minimum value.

g'(x)=2(x-2)

0=2(x-2)

x=2

Evaluatinf g(x) at this value of x we have:

g(2)=(2-2)^{2}+3

g(2)=3

<u>Then, the minimum point of this function is (2,3) and it corresponds to (B)</u>

48)

Let's use the same method here.

g(x)=f(x)-3

g(x)=(x-2)^{2}+1-3

g(x)=(x-2)^{2}-2

Let's find the first derivative and equal to zero to find x and y minimum value.

g'(x)=2(x-2)

0=2(x-2)

x=2

Evaluatinf g(x) at this value of x we have:

g(2)=(2-2)^{2}-2

g(2)=-2

<u>Then, the minimum point of this function is (2,-2) and it corresponds to (D)</u>

<u />

I hope it helps you!

<u />

8 0
3 years ago
Can someone explain what these types of arrows mean please?
Yakvenalex [24]
I think it means grater or less ? Or positive or negative?
8 0
3 years ago
the granola summer buys used to cost six dollars per pound but it has been marked up 15% a how much did it cost summer to buy 2.
EastWind [94]
17.94
Because 15% of $6 is .9 so 
2.6x6.9=17.94
5 0
3 years ago
Please help, I can figure out 20 shares multiply by $117.98 =2359.69
11Alexandr11 [23.1K]

Answer:

The awnser is D hope this helps :)

Step-by-step explanation:


4 0
3 years ago
How would you find 1/11 is as a decimal using a calculator?
marishachu [46]

Answer:

divide 11 by 1. the answer would be 0.0909

Step-by-step explanation:

if you have a graphing calculator then you have the option to put it in as a fraction and then you would put it into a decimal. and if not then you could do it on paper.

3 0
3 years ago
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