A(n)=4+4(n-1)
a(n)=4+4n-4
a(n)=4n
76=4n
n=19
The sum of any arithmetic sequence (series are infinite) is:
(a+a(n))(n/2)
The average of the first and last terms times the number of terms, in this case we found that n=19 so:
19(4+76)/2=760
Answer:
Option B 1/64
Step-by-step explanation:
Hope this helps
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total outcomes r = 36
multiples of 3 = 3,6
total outcomes of multiple fo 3 = 12
12/36 = 1/3
1/3 is the answer
Hope it helps!
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76, 84, 93, 67, 82, 87, & 76
The mean is just the middle number of the data set,
Start by rewriting the set in order from smallest to biggest:
67, 76, 76, 82, 84, 87, 93
Determine which is the number in the middle,
67, 76, 76, *82*, 84, 87, 93
So, in this case, the median is 82.
Since 1/2 is one half, the rise must be half of the run, meaning that the rise would be 25.
