Question

C. ax + bx = 10

Answer 1

Answer:

$x=\frac{10}{a+b}$ with $a \neq -b$.

Step-by-step explanation:

So we have:

$ax+bx=10$ and we are solving for $x$.

We want to get all terms that have x on one side and all terms without x on the opposing side.  This is actually already done.

Now we are going to factor the side that has the x's.  We are going to factor x out.

$x(a+b)=10$

Now you have a number times x and you want x by itself. The inverse operation of multiplication is division. So we are going to divide both sides by $(a+b)$:

$x=\frac{10}{a+b}$

You could probably stop here but just in case....

$a+b$ can't be 0 because then you would have 10/0 which is not a number.

So if we solve $a+b=0$ we can find out what we don't want and b to be:

$a+b=0$

Subtract b on both sides:

$a=-b$

So we we don't want $a$ and $-b$ to be the same value.

Answer 2

Answer:

10/a+b=x

Step-by-step explanation:

Divide both sides by a+b