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2 years ago

Find the equation of a line that passes through (5,-3) and is perpendicular to y = x.

1 answer:

8 0

We know the slope is -1, because perpendicular line's slopes are always the negative reciprocal. We plug (5, -3) in to get:
-3 = -5 + b
b = 2
So we get C. y = -x + 2.
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Hope this helps!
==jding713==

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Which expressions are equivalent to ? Check all that apply.

GrogVix [38]

Answer:

6.2+8.7+8.9x

Step-by-step explanation:

For expressions to be equivalent, they must simplify to the same lowest form. 8.9x+6.2+8.7 simplifies to 8.9x +14.9.

Each of the expressions below must simplify to 8.9x + 14.9 to be equivalent.

9x+6+9 = 9x + 15 NO

3.9+6.2+8.7x = 8.7x + 10.1 NO

3.7+8.9+6.2 = 18.8 NO

6.2+8.7+8.9 = 23.8 NO

6.2+8.7+8.9x = 8.9x + 14.9 YES

3.9+6.2x+8.7 = 6.2x + 12.6 NO

3.9x+8.7+6.2 = 3.9x + 14.9 NO

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3 years ago

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Which of the following describes a compound event? A) getting heads on a coin toss B) rolling an odd number on a die C) getting

jekas [21]

Combination event: 2 or more simple events/actions
The correct answer is D) because there are 2 actions in one description.

3 0

2 years ago

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Point N ( , 2 9) is on RS. A translation moves point N to its image, N'(6 3 , ). What is the distance, in units, between any poi

KatRina [158]

Hello!

Distance between two points (2,9) and (6,3) -

1. Take the Absolute Difference between the X points 2 and 6. The Absolute Difference is 4. 
2. Square 4 = 16 
3. Take the Absolute Difference between the Y points 9 and 3. The absolute Difference is 12. 
4. Square 12 = 144 
5 Add 144 + 16 = 160 
6. Take the Square root of 160 

12.6491106407

Hope this Helps at least! :)

7 0

3 years ago

A huge ice glacier in the Himalayas initially covered an area of 454545 square kilometers. Because of changing weather patterns,

zloy xaker [14]

Answer:

$t=-20ln\left(\dfrac{1}{3}\right)$

Step-by-step explanation:

The relationship between A, the area of the glacier in square kilometers, and t, the number of years the glacier has been melting, is modeled by the equation.:

$A=45e^{-0.05t}$

We want to determine the value of t for which the area, A(t)=15 square kilometers.

$15=45e^{-0.05t}\\$Divide both sides by 45\\\dfrac{15}{45} =\dfrac{45e^{-0.05t}}{45}\\\dfrac{1}{3}=e^{-0.05t}\\$Take the natural logarithm of both sides\\ln\left(\dfrac{1}{3}\right)=ln\left(e^{-0.05t}\right)\\ln\left(\dfrac{1}{3}\right)=-0.05t\\$Divide both sides by -0.05$\\t=-\dfrac{ln\left(\dfrac{1}{3}\right)}{0.05} \\=-\dfrac{ln\left(\dfrac{1}{3}\right)}{0.05}\\t=-20ln\left(\dfrac{1}{3}\right)$

Therefore, the time for which the area will be 15 sqyare kilometers is:

-20 ln(1/3) years.

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3 years ago

Answer for 4x+4=2x+8

abruzzese [7]

Answer:

x=2

Step-by-step explanation:

7 0

3 years ago

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