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2 years ago

Find the equation of a line that passes through (5,-3) and is perpendicular to y = x.

1 answer:

8 0

We know the slope is -1, because perpendicular line's slopes are always the negative reciprocal. We plug (5, -3) in to get:
-3 = -5 + b
b = 2
So we get C. y = -x + 2.
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Hope this helps!
==jding713==

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Can you please help

ololo11 [35]

Answer:

1/12 inches

If it is Reduced could be 1/6
7 - 6 = 1

So it’s 1

Step-by-step explanation:

3 0

1 year ago

Read 2 more answers

The length of the box is 2x - 2 and the width is x - 5. Find the perimeter. (HINT: p= 2L + 2W) Choose one.

trasher [3.6K]

Answer:

Option D: 6x-14 is the correct answer.

Step-by-step explanation:

Given that:

Length of the box = L = 2x-2

Width of the box = W = x-5

Perimeter is defined by the sum of length of all sides of the box.

Perimeter of the box = P = 2L + 2W

Perimeter of box = 2(2x-2) + 2(x-5)

Perimeter = 4x-4+2x-10

Perimeter = 6x-14

The perimeter of the box is 6x-14.

Hence,

Option D: 6x-14 is the correct answer.

6 0

2 years ago

Brand A scooter has a top speed that goes 4 miles per hour faster than Brand B. If after 5 hours, Brand A scooter traveled 75 mi

Travka [436]

Answer:

11MPH

Step-by-step explanation:

I DIVIDED 75 AND 5 =11 HOPE THIS HELP

5 0

2 years ago

Max installed a motion detector on the shed that illuminates a semicircle with a radius of 12 ft. What is the area of the yard t

Jobisdone [24]

You didn't give enough information. We don't know the yard size.

5 0

2 years ago

I don’t understand this help please

Elodia [21]

Answer:

Step-by-step explanation:

The first simplification we can make is to replace 6^0 with 1.

The first rules of exponents we can apply are ...

(a·b)^c = a^c·b^c . . . . . . similar to the distributive property

 (a^b)^c = a^(b·c)

This reduces your expression to ...

$(2^8\cdot 3^{-5})^{-2}\cdot\left(\dfrac{3^{-2}}{2^3}\right)^4\cdot 2^{28}=2^{8(-2)}\cdot 3^{-5(-2)}\cdot\dfrac{3^{-2(4)}}{2^{3(4)}}\cdot 2^{28}\\\\=2^{-16}\cdot 3^{10}\cdot\dfrac{3^{-8}}{2^{12}}\cdot 2^{28}$

Now we can apply another two rules of exponents:

 (a^b)(a^c) = a^(b+c)

 1/a^b = a^-b

Using these, we have ...

$=2^{-16-12+28}\cdot 3^{10-8}\\\\=2^0\cdot 3^2\\\\=1\cdot 9=9$

The value of the expression is 9.

3 0

3 years ago