Figures of speech that can make oral style more vivid include

1 answer:

4 0

A figure of speech deviates from the ordinary, expected meanings of words to make a description or comparison unique, vivid, and memorable. Common figures of speech include metaphors, similes, and personification.

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Which group of colonists established the first free public education system?

IRISSAK [1]

New England Colonists

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3 years ago

True or false. Resources that are commonly owned are likely to be over-utilized and poorly maintained.

mel-nik [20]

Answer:

True

Explanation:

As the use of the resources depends on its availability and the accessibility and thus is an important component in the use and those resources that are overused and mostly used are more likely to be poorly maintained and are at times overused and as they are common and essential for the life such as the forest resources and water resources and land resource.

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26. A standard deck of playing cards consists of 52 cards, half of which are black and half of which are red. If three cards are

nlexa [21]

Answer:

1/4

Explanation:

The probability of getting one black card out of a 52 deck of cards (where 26 are red and 26 are black) is: $\frac{26}{52}$ , (remember that probability of an event = (total amount of favorable outcomes/ total amount of outcomes) by simplifying this fraction we get: $\frac{26}{52} = \frac{13}{26}=\frac{1}{2}$ .

Therefore, the probability of getting one black card out of a deck of 52 cards is 1/2.

Since the way of picking cards is done with replacement, for the second card, if we want to get another black one we would have a probability of 1/2.

Again, for the third card we would still have a probability of 1/2 of getting a black one.

We want to get a black one on the first time AND on the second AND on the third one, therefore we have to use the rule of multiplication, which tells us we have to multiply all three probabilities:

P(having 3 black cards) = $(\frac{1}{2}) (\frac{1}{2})(\frac{1}{2})= \frac{1}{8}$

Applying the same way of thinking that we used before but now for the red cards (which are also 26) we have that the probability of getting one red card is 1/2

Thus,

P(having 3 red cards) = $(\frac{1}{2}) (\frac{1}{2})(\frac{1}{2})= \frac{1}{8}$

Since the problem is asking us to get either 3 black cards OR 3 red cards, we are going to use the rule of sum and we're going to sum up both probabilities.

P(having 3 black cards OR 3 red cards) = $\frac{1}{8} + \frac{1}{8} = \frac{2}{8} = \frac{1}{4}$