Answer:
Largest possible value for the 3rd side can be 22.
Step-by-step explanation:
Property of sides of a triangle:
If two sides of a triangle are 
and 
long, then the length of third side 
must be:
i.e. the sum of two sides and must be greater than the third side .
So, to find the largest possible value:
Largest possible value of can be lesser than 23.
i.e. <em>22</em> can be the largest possible value of the third side.
A. Long division
Multiply x-4 by x^2 to get x^3-4x^2. Subtract product
(x^3-7x-6) - (x^3-4x^2) = 4x^2-7x-6
Now multiply x-4 by 4x to get 4x^2-16x. Subtract product
(4x^2-7x-6) - (4x^2-16x) = 9x-6
Now multiply x-4 by 9 to get 9x-36. Subtract product
(9x-6) - (9x-36) = 30
Remainder = (x^3-7x-6)/(x-4) = 30
B. using the Polynomial Remainder Theorem
which says that if a polynomial f(y) is divided by a linear expression (x-a), the remainder equals f(a).
Here f(x)=x^3-7x-6, and (x-a)=(x-4)), i.e. a=4
according to the Polynomial Remainder Theorem,
Remainder = f(4) = (4)^3-7(4)-6 = 64-28-6 = 30 (as before)
475 = 400 + 70 + 5
therefore
9 × 475 = 9 × (400 +70 + 5) = 9 × 400 + 9 × 70 + 9 × 5
=3600 + 630 + 45 = 4275
I think... It's better to use Distributive Property:
(a - b) × c = a × c - b × c
9 = 10 - 1
therefore:
<span>(10 - 1) ×475 = 10 × 475 - 1 × 475 = 4750 - 475 = 4275</span>
The probability that the first success occurs on the third trial is 0.125.
Answer: Option C
<u>Step-by-step explanation:</u>
The probability of success is given by the geometric distribution formula:
Where,
p = probability of success for single trial.
q = probability of failure for a single trial (1-p)
x = the number of failures before a success.
P(X = x) = Probability of x successes in n trials.
<u>Given:
</u>
p = 19% = 0.19
q = 1 – p = 1 – 0.19 = 0.81
x = 3
We want to find the probability that the first success occurs on the third trial so,
Answer:
_
113 -✓5
Step-by-step explanation:
_
113-(-(-✓5))
_
=113-✓5 (decimal:110.763932)
