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tensa zangetsu [6.8K]
3 years ago
5

Find the distance between points A(2,3) and B(5,9) round to the nearest tenth

Mathematics
1 answer:
olya-2409 [2.1K]3 years ago
4 0

To calculate the distance between two points, we can use a formula that is a variation Pythagorean Theorem. Look:


\mathsf{d=\sqrt{(x_B-x_A)^2+(y_B-y_A)^2}}


"d" represents the distance and coordinates are expressed as follows: (x, y)


Let's go to the calculations.


\mathsf{d=\sqrt{(x_B-x_A)^2+(y_B-y_A)^2}}\\\\ \mathsf{d=\sqrt{(5-2)^2+(9-3)^2}}\\\\ \mathsf{d=\sqrt{(3)^2+(6)^2}}\\\\ \mathsf{d=\sqrt{9+36}}\\\\ \mathsf{d=\sqrt{45}}\\\\ \mathsf{d=6.7082039324993690892275210061938...}\\\\ \underline{\mathsf{d\approxeq6.7}}



The answer is 6.7 uc.

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Answer:

BD = <u>1</u> unit

AD = <u>1</u> unit

AB = <u>1.6</u> units

AC = <u>1.6</u> units

Step-by-step explanation:

In the picture attached, the triangle ABC is shown.

Given that triangle ABC is isosceles, then ∠B = ∠C

∠A + ∠B + ∠C = 180°

36° + 2∠B = 180°

∠B = (180° - 36°)/2

∠B = ∠C  = 72°

From Law of Sines:

sin(∠A)/BC = sin(∠B)/AC = sin(∠C)/AB

(Remember that BC is 1 unit long)

AB = AC = sin(72°)/sin(36°) = 1.6

In triangle ABD, ∠B = 72°/2 = 36°, then:

∠A + ∠B + ∠D = 180°

36° + 36° + ∠D = 180°

∠D =  180° - 36° - 36° = 108°

From Law of Sines:

sin(∠A)/BD = sin(∠B)/AD = sin(∠D)/AB

(now ∠A = ∠B)

BD = AD = sin(∠A)*AB/sin(∠D)

BD = AD = sin(36°)*1.6/sin(108°) = 1

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3 years ago
Which one represents a line which is parallel to the line y=-7x-4
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Step-by-step explanation:

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According to the question, the line is through the points (0,5) and (-2,11)

To calculate the slope using standard formula that is :

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The slope-intercept form is:y = -3x+5

What is the equation of the line?

To represent the set of points in an algebraic form is known as the equation of line. The set of points represent lines in the coordinate system. The parameters can be calculated and those parameters are slope and y-intercept.

To learn more about the equation of the line from the given link:

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