Set the equation equal to zero.
9x+6=0
Subtract 6 from both sides
9x = -6
Divide both sides by 9
x=-6/9
or -2/3
2(5x-3)=0
Distribute
10x-6=0
add 6 to both sides
10x=6
Divide by 10 on both sides
x=6/10 or 4/5
5y+14=0
-14 from both sides
5y=-14
divide both sides by 5
y=-14/5
or -2 and 4/5
" the difference " means subtract
the difference of twice a number and 3...
2x - 3 <== ur expression
Sub in 2 for x and solve for y
x + 3 = y
2 + 3 = y
5 = y
so ur points are : (2,5)
Answer:
The hypotenuse is 5
Step-by-step explanation:
We can use the Pythagorean theorem to find the hypotenuse of a right triangle
a^2 +b^2 =c^2 where a and b are the legs and c is the hypotenuse
3^2 +4^2 =c^2
9+16=c^2
25=c^2
Take the square root of each side
sqrt(25) =sqrt(c^2)
5 = c
