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denpristay [2]
3 years ago
10

If a ball is dropped near the surface of the earth, then the distance it falls is directly proportional to the square of the tim

e it has fallen. A ball is dropped over the edge of a vertical cliff and falls 39.2 meters in two seconds. Determine the distance (in meters) the ball would have dropped in 3.5 seconds.
Mathematics
2 answers:
damaskus [11]3 years ago
7 0
ABOUT 143.2 meters im pretty sure

vivado [14]3 years ago
3 0
Answer: 120 m

Explanation:

1) That the distance fallen is directly proportion of the square of the time, means:

distance = k * t^2 => k = distance / t^2

2) Use it for the two set of data given:

a)  39.2 m, 2 s => k = 39.2 m / (2 s)^2

b) x, 3.5 s => k = x / (3.5 s)^2

3) Equal the two expressions for k:

39.2 m / (2s)^2 = x / (3.5s)^2

=> x = 30.2 m * (3,5s)^2 / (2s)^2 = 39.2m * 12.25 / 4 = 120.05m = 120 m
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Answer:

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Step-by-step explanation:

<u>Given</u>

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<u>Convert to point slope form</u>

y - y1 = m(x - x1)

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<u>Distribute -4/3</u>

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<u>Add seven in both sides</u>

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y = -4/3x + 17/2

<u>Answer</u>

linear equation: y = -4/3x + 17/2

point-slope form: y - 7 = -4/3(x + 1)

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