Bianca's bank offers a savings account with a 2.1% APR,
compounded monthly. The the actual annual percentage yield on this account can
be calculated using i = (1+ r/m)^m, where i is the actual APR, r is the nominal
interest rate and m the compounding period in a year. APR is equal to 2.12%
Answer:
24/49
Step-by-step explanation:
Let's add the terms and see if there's a pattern

Suppose we say the sum of n terms is (n/(2n+1)), the next term in the series will be 1/((2n+1)(2n+3)) and adding that to the presumed sum gives ...

Then it appears the sum of n terms is (n/(2n+1)). So, the sum of 24 terms is ...

Answer:
(Correct to 4 decimal places)
Step-by-step explanation:
The probability of a continuous normal variable X found in a particular interval [a, b] is the area under the curve bounded by x=a and x=b and is given by:

where




Using a calculator,
Answer: 17. is A and 18 is most likely G
Step-by-step explanation: