Answer:
(9-10x)(9+10x) (I think this is the answer but I'm not one hundred percent sure)
Step-by-step explanation:
First, you can recognize that both numbers (-100x^2 and 81) are a difference of squares, in which means that they both can be square routed. Then, plug in the square routes of the numbers into (9-10x)(9+10x). 9 is the square route of 81 and 10 is the square route of 100. Make sure that when you put the numbers in the parenthesis that there is one negative and positive number since a negative multiplied by a positive makes a negative, hence making 100 negative. I hope that helped.
3751×2=7502
15002÷2=7502
250+7252=7502
7502+0=7502
2236.8 to the nearest ten would be 2240. Hope this helps. If you need help with anything else, feel free to message me. :)
<u>Given</u>:
The given equations are
and 
We need to determine the pair of numbers that is a member to the system of equations.
<u>Pair of numbers:</u>
The pair of numbers can be determined by solving the system of equations.
Let us use the substitution method to solve the equations.
Substituting
in the equation
, we have;




Thus, the value of x is 1.
Substituting x = 1 in the equation
, we get;



Thus, the value of y is 7.
Hence, the pair of numbers that is a member of both the equations are (1,7)