Can somebody tell the answer????

Your race car weighs 1.5 tons. To make the car faster, you replaced the steel body with carbon-fiber and reduced the weight by 3

Scorpion4ik [409]

One ton = 2000 lbs
Therefore, 1.5 tons = 3000 lbs
3000-300=2700lbs

5 0

2 years ago

A person stands 10 meters east of an intersection and watches a car driving towards the intersection from the north at 13 meters

In-s [12.5K]

Answer:

Therefore the rate change of distance between the car and the person at the instant, the car is 24 m from the intersection is 12 m/s.

Step-by-step explanation:

Given that,

A person stand 10 meters east of an intersection and watches a car driving towards the intersection from the north at 13 m/s.

From Pythagorean Theorem,

(The distance between car and person)²= (The distance of the car from intersection)²+ (The distance of the person from intersection)²+

Assume that the distance of the car from the intersection and from the person be x and y at any time t respectively.

∴y²= x²+10²

$\Rightarrow y=\sqrt{x^2+100}$

Differentiating with respect to t

$\frac{dy}{dt}=\frac{1}{2\sqrt{x^2+100}}. 2x\frac{dx}{dt}$

$\Rightarrow \frac{dy}{dt}=\frac{x}{\sqrt{x^2+100}}. \frac{dx}{dt}$

Since the car driving towards the intersection at 13 m/s.

so, $\frac{dx}{dt}=-13$

$\therefore \frac{dy}{dt}=\frac{x}{\sqrt{x^2+100}}.(-13)$

Now

$\therefore \frac{dy}{dt}|_{x=24}=\frac{24}{\sqrt{24^2+100}}.(-13)$

$=\frac{24\times (-13)}{\sqrt{676}}$

$=\frac{24\times (-13)}{26}$

= -12 m/s

Negative sign denotes the distance between the car and the person decrease.

Therefore the rate change of distance between the car and the person at the instant, the car is 24 m from the intersection is 12 m/s.

8 0

2 years ago

Hadley has 3/6 of a box of white envelopes and 1/3 of a box of gray envelopes. When full, each box of envelopes has the same num

QveST [7]

Answer:

The two statements that apply are A and B.

Step-by-step explanation:

1. Let's review the information given to us to answer the question correctly:

White envelopes Hadley has = 3/6 of a box

Gray envelopes Hadley has = 1/3 of a box

When full, each box of envelopes has the same number of envelopes

Hadley said she has 4/9 of a box when she puts the white envelopes and gray envelopes together.

2. Which statements describe this situation? Select the two statements that apply.

Let's add 3/6 and 1/3

3/6 + 1/3 = 3/6 + 2/6 = 5/6

A. Hadley’s answer is incorrect, because 3/6 is equal to 1/2 , and 4/9 is less then 1/2 . This is correct.

B. Hadley's answer is incorrect, because 3/6 plus 1/3 equals 5/6. This is correct.

C. Hadley's answer is incorrect, because 3/6 plus 1/3 equals 2/6. This is wrong

D. Hadley's answer is correct, because 3 and 1 is 4, and 6 and 3 is 9. This is wrong.

The two statements that apply are A and B.

3 0

3 years ago

Combina los términos semejantes -16 + 8x +20x -5y

mrs_skeptik [129]

28x+-21 you simplify them first

7 0

3 years ago

Read 2 more answers

If a liquid weighs 2 pounds and has capacity 3 gallons. What is its density

brilliants [131]

8+ the product of 2 and a number to the third power, what it means 2×m cubed. So it is 8+2m (cubed)

hope it helps

6 0

3 years ago

Read 2 more answers

Can somebody tell the answer????​

Can somebody tell the answer????