The expected value of the game is the mean value of the game
The expected value of the game is $1
<h3>How to determine the expected value?</h3>
There are 13 spades in a deck of card of 52
So, the probability of selecting a spade is:
P(Spade) = 13/52
Simplify
P(Spade) = 1/4
Winning = $7
The probability of not selecting a spade is:
P(Not spade) = 1 - 1/4
Simplify
P(Not spade) = 3/4
Lose = $1
The expected value of the game is:

This gives

Simplify

Evaluate

Hence, the expected value of the game is $1
Read more about expected values at:
brainly.com/question/15858152
2^3z^9
A for question 1=8z^9
(-8ab)^2
(-8^2a^2b^2)
A for question 2=64a^2b^2
6 (x^3)^2
6 x^6
6x^6
Enjoy!=)