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2 years ago

Please help i have no idea what this is!!

Mathematics

2 answers:

Nesterboy [21]2 years ago

7 0

Answer:

Step-by-step explanation:

y - y1 = m (x - x1)

y1 = 3

x1 = 5

m(the slope)= -12

Harlamova29_29 [7]2 years ago

6 0

Answer:

l think it A

Step-by-step explanation:

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Jimmy receives his first 3 video games free then pays $50 for each game after that. Is the amount of money he spends on video ga

bagirrra123 [75]

no and that's the answer.

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3 years ago

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Which is an example of an algebraic expression?

azamat

An algebraic expression doesnt have an equals sign or an inequality sign.

So,

A is an expression
B is an inequality
C is an equation
D is an in inequality

So the answer is A

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3 years ago

Each contestant in the Hunger Games must be trained to compete. Suppose that the time it takes to train a contestant has mean 5

LiRa [457]

Answer:

11.51% probability that it will take less than 450 days to train all the contestants.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

When the distribution is normal, we use the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For the sum of n variables, the mean is $\mu*n$ and the standard deviation is $s = \sigma\sqrt{n}$

In this question:

$n = 100, \mu = 100*5 = 500, s = 4\sqrt{100} = 40$

Approximate the probability that it will take less than 450 days to train all the contestants.

This is the pvalue of Z when X = 450.

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$

$Z = \frac{450 - 500}{40}$

$Z = -1.2$

$Z = -1.2$ has a pvalue of 0.1151

11.51% probability that it will take less than 450 days to train all the contestants.

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3 years ago

13. Victoria uses 1 cup of flavored syrup to

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Answer:

Victoria can Make 2 more Italian sodas

Step-by-step explanation:

She had 3 but used one so 3 - 1 = 2 then she has two more so 2 + 1 = 3

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2 years ago

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A store finds that its sales revenue changes at a rate given by S'(t) = −30t2 + 420t dollars per day where t is the number of da

allochka39001 [22]

Answer:

Step-by-step explanation:

Give the rate of change of sales revenue of a store modeled by the equation $S'(t)= -30t^{2} + 420t$ . The Total sales revenue function S(t) can be gotten by integrating the function given as shown;

$\int\limits {S'(t)} \, dt = \int\limits ({-30t^{2}+420t }) \, dt \\S(t) = \frac{-30t^{3} }{3}+\frac{420t^{2} }{2}\\ S(t)= -10t^{3} +210t^{2} \\$

a) The total sales for the first week after the campaign ends (t = 0 to t = 7) is expressed as shown;

$Given\ S(t) = -10t^{3} + 210t^{2}$

$S(0) = -10(0)^{3} + 210(0)^{2}\\S(0) = 0\\S(7) = -10(7)^{3} + 210(7)^{2}\\S(7) = -3430+10,290\\S(7) = 6,860$

Total sales = S(7) - S(0)

= 6,860 - 0

Total sales for the first week = $6,860

b) The total sales for the secondweek after the campaign ends (t = 7 to t = 14) is expressed as shown;

Total sales for the second week = S(14)-S(7)

Given S(7) = 6,860

To get S(14);

$S(14) = -10(14)^{3} + 210(14)^{2}\\S(14) = -27,440+41,160\\S(14) = 13,720$

The total sales for the second week after campaign ends = 13,720 - 6,860

= $6,860

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3 years ago