<span>f(x)=2x
f(1)=2*1=2
f^2(1)=2*2*1=4
f^3(1) =2*2*2*1=8
1. If you
continue this pattern, what do you expect would happen to the numbers as
the number of iterations grows?
I expect the numbers continue growing multiplying each time by 2.
Check your result by conducting at
least 10 iterations.
f^4(1) = f^3(1) * f(1) = 8*2 = 16
f^(5)(1) = f^4(1) * f(1) = 16 * 2 = 32
f^6 (1) = f^5 (1) * f(1) = 32 * 2 = 64
f^7 (1) = f^6 (1) * f(1) = 64 * 2 = 128
f^8 (1) = f^7 (1) * f(1) = 128 * 2 = 256
f^9 (1) = f^8 (1) * f(1) = 256 * 2 = 512
f^10 (1) = f^9 (1) * f(1) = 512 * 2 = 1024
2. Repeat the process with an initial value of −1.
What happens as the number of iterations grows?
f(-1) = 2(-1) = - 2
f^2 (-1) = f(-1) * f(-1) = - 2 * - 2 = 4
f^3 (-1) = f^2 (-1) * f(-1) = 4 * (-2) = - 8
f^4 (-1) = f^3 (-1) * f(-1) = - 8 * (-2) = 16
f^5 (-1) = f^4 (-1) * f(-1) = 16 * (-2) = - 32
As you see the magnitude of the number increases, being multiplied by 2 each time, and the sign is aleternated, negative positive negative positive ...
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This can be put into a formula like so:
Since they are 6 consecutive even numbers, they will alternate odd/even/odd/even.
x, x+2, x+4, x+6, x+8, x+10 = 126
Simplify
6x + 30 = 126
6x = 96
x = 16
And you want the fourth number, so plug the x value back into the equation of 'x+6' and you will get 16+6 which = 22.
Answer:
2995
Step-by-step explanation:
The first quartile (Q1) is defined as the middle number between the smallest number and the median of the data set
1127
1482
2995
3009
3250
3250
3445
3449
4000
6120
rearranging the data sets from the least to the highest
the middle number of the data sets is 3250
the middle number between the smallest number and the median of the data set is 2995
Answer:
x=20
y=?
Step-by-step explanation:
Answer:
6.87022901%
Step-by-step explanation:
He measured 14 out of 13.1 inches. There is a difference of 0.9 inches when u subtract. He miscalculated by 0.9 out of 13.1. In a calculator you divide .9 by 13.1 you get 0.0687022901. Multiply by 100 to get the percent and round it to your desired decimal place.
