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Alla [95]
3 years ago
13

100.0 mL of a 0.500 M solution of KBr is diluted to 500.0 mL. What is the new concentration of the solution

Chemistry
1 answer:
andreyandreev [35.5K]3 years ago
3 0

Answer:

0.1 M

Explanation:

The following data were obtained from the question:

Initial volume (V1) = 100 mL

Initial concentration (C1) = 0.5 M

Final volume (V2) = 500 mL

Final concentration (C2) =?

Using the dilution formula C1V1 = C2V2, the new concentration of the solution can be obtained as follow:

C1V1 = C2V2

0.5 × 100 = C2 × 500

50 = C2 × 500

Divide both side by 500

C2 = 50/500

C2 = 0.1 M

Therefore, the new concentration of the solution is 0.1 M

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Answer:

<h3>The answer is 7.42 </h3>

Explanation:

The pH of a solution can be found by using the formula

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From the question we have

pH =  -  log(3.8 \times  {10}^{ - 8} )  \\  = 7.420216...

We have the final answer as

<h3>7.42 </h3>

Hope this helps you

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