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Alla [95]
2 years ago
13

100.0 mL of a 0.500 M solution of KBr is diluted to 500.0 mL. What is the new concentration of the solution

Chemistry
1 answer:
andreyandreev [35.5K]2 years ago
3 0

Answer:

0.1 M

Explanation:

The following data were obtained from the question:

Initial volume (V1) = 100 mL

Initial concentration (C1) = 0.5 M

Final volume (V2) = 500 mL

Final concentration (C2) =?

Using the dilution formula C1V1 = C2V2, the new concentration of the solution can be obtained as follow:

C1V1 = C2V2

0.5 × 100 = C2 × 500

50 = C2 × 500

Divide both side by 500

C2 = 50/500

C2 = 0.1 M

Therefore, the new concentration of the solution is 0.1 M

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Tomtit [17]

Answer:

69.7% is percent yield

Explanation:

Based on the reaction:

3Ca(NO3)2(aq) + 2Na3PO4(aq) → Ca3(PO4)2(s) + 6NaNO3(aq)

2 moles of Na3PO4 react producing 6 moles of NaNO3.

As 24.2 moles of Na3PO4 react, theoretical moles of NaNO3 produced are:

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2 years ago
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Hey there!:

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hope this helps!</span>
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