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kipiarov [429]
3 years ago
13

Find all polar coordinates of point P = (6, 31°).

Mathematics
2 answers:
lesya692 [45]3 years ago
7 0

Answer:

All polar coordinates of point P = (6, 31°) are P=(6,\frac{31\pi}{180}+2n\pi) and P=(-6,\frac{31\pi}{180}+(2n+1)\pi) where, n is an integer.

Step-by-step explanation:

The given polar coordinates of a point are

P=(6,31^{\circ})

If a point is defined as

P=(r,\theta)

Where, θ is in radian, then the polar coordinates of that points are

(r,\theta)=(r,\theta+2n\pi)

(r,\theta)=(-r,\theta+(2n+1)\pi)

Where, n is an integer.

The given point in radian form is

P=(6,31\times \frac{\pi}{180})

P=(6,\frac{31\pi}{180})

All polar coordinates of point P = (6, 31°) are

P=(6,\frac{31\pi}{180}+2n\pi)

P=(-6,\frac{31\pi}{180}+(2n+1)\pi)

Where, n is an integer.

alex41 [277]3 years ago
3 0
(6,(31pi/180)+2 n pi) (-6,(31pi/180)+2 n pi) <span>
</span>
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