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3 years ago

Solve for f in the proportion. 28/44 = F/99 F = ?

Mathematics

1 answer:

victus00 [196]3 years ago

5 0

Answer:

F = 63

Step-by-step explanation:

28/44 = F/99

28/44 x 99 = F

F = 63

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I tried to solve this problem and can’t can you tell me the answer

Kitty [74]

6/8 because maybe you could try the butterfly strategy and the answer would probably be 6/8

6 0

3 years ago

The owner of an auto repair shop studied the waiting times for customers who arrive at the shop for an oil change. The following

labwork [276]

Answer:

(d)0.6

Step-by-step explanation:

(a)Frequency Distribution

$\left|\begin{array}{c|c}$Waiting Time(in Minutes)&$Frequency\\-----------&--\\0-4&4\\5-9&8\\10-14&5\\15-19&2\\20-24&1\\--&--\\Total&20\end{array}\right|$

(b)The relative frequency distribution.

$\left|\begin{array}{c|c}$Waiting Time(in Minutes)&$Relative Frequency\\-----------&--\\0-4&4/20=0.2\\5-9&8/20=0.4\\10-14&5/20=0.25\\15-19&2/20=0.1\\20-24&1/20=0.05\\--&--\\Total&1\end{array}\right|$

(c)The cumulative frequency distribution.

$\left|\begin{array}{c|c|c}$Waiting Time(in Minutes)&$Frequency&$Cumulative Frequency\\-----------&--&---\\0-4&4&4\\5-9&8&12\\10-14&5&17\\15-19&2&19\\20-24&1&20\\--&--&--\\Total&20\end{array}\right|$

(d)The proportion of customers needing an oil change who wait 9 minutes or less.

Proportion of customers needing an oil change who wait 9 minutes or less.

$=\dfrac{12}{20} \\\\=0.6$

5 0

3 years ago

The perimeter of a rectangle is 50 feet and its area is 154 feet. What are the dimensions of the

sasho [114]

14 and 11 are it dimensions

Hope this helps!

3 0

3 years ago

An equation parallel and perpendicular to 4x+5y=19

UNO [17]

Answer:

Parallel line:

$y=-\frac{4}{5}x+\frac{9}{5}$

Perpendicular line:

$y=\frac{5}{4}x-\frac{1}{2}$

Step-by-step explanation:

we are given equation 4x+5y=19

Firstly, we will solve for y

$4x+5y=19$

we can change it into y=mx+b form

$5y=-4x+19$

$y=-\frac{4}{5}x+\frac{19}{5}$

so,

$m=-\frac{4}{5}$

Parallel line:

we know that slope of two parallel lines are always same

so,

$m'=-\frac{4}{5}$

Let's assume parallel line passes through (1,1)

now, we can find equation of line

$y-y_1=m'(x-x_1)$

we can plug values

$y-1=-\frac{4}{5}(x-1)$

now, we can solve for y

$y=-\frac{4}{5}x+\frac{9}{5}$

Perpendicular line:

we know that slope of perpendicular line is -1/m

so, we get slope as

$m'=\frac{5}{4}$

Let's assume perpendicular line passes through (2,2)

now, we can find equation of line

$y-y_1=m'(x-x_1)$

we can plug values

$y-2=\frac{5}{4}(x-2)$

now, we can solve for y

$y=\frac{5}{4}x-\frac{1}{2}$

4 0

3 years ago

Julian jogs 222 kilometers east, 444 kilometers north, and then 777 kilometers west. how far is julian from his starting positio

lawyer [7]

If you would like to know how far is Julian from his starting position, you can calculate this using the following steps:

First, you have to make a right triangle, where the hypotenuse of this triangle will actually be the distance we are looking for. The distances of the other two sides are 444 kilometers, and 777 kilometers - 222 kilometers; to be exact: 444 kilometers and 555 kilometers.

The distance we are interested in ... d:
d^2 = 444^2 + 555^2
d^2 = 197136 + 308025 = 505161
d = sqrt(505161)
d = <span>710.7 kilometers
</span>
The correct result would be <span>710.7 kilometers.</span>

7 0

3 years ago