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monitta
3 years ago
6

A movie rental company offers a membership plan that costs $10/month and charges $2 to rent each movie. How many movies can a me

ntor rent in one month and spend at most $24? Write and solve the linear inquality..... Right Answer Will Be Crowned TYPE SOMETHING OTHER THAN THE ANSWER WILL GET DELETED! CORRECT ANSWER GET 50 POINTS
Mathematics
1 answer:
Brums [2.3K]3 years ago
8 0

Answer:

See below

Step-by-step explanation:

linear equation: y=2x+10

x=cost per movie rented

10=$10 for the membership

24=2x+10    (24 being total you want to spend)

subtract 10 from each side

14=2x

divide by 2

7=x

He can rent no more than 7 movies if he want to spend $24 or less in the month

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200 people whee asked how often they go to the movies and whether they prefer action or drama. If 144 people went to the movies
Alex Ar [27]

Answer:

It would be 72% trust me it is correct because this level of questions seems a little to young for me lol

Step-by-step explanation:

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2 years ago
The area of a rectangle is 63m^2 and the length of the rectangle is 11m more than twice the width. Find the length and width.
AleksandrR [38]

Answer:

width = 3.5 m

length = 18 m

Step-by-step explanation:

area = length x width

x is the width then length = 2x + 11

x(2x + 11) = 63

2x^2 + 11x - 63 = 0

The formula to solve a quadratic equation of the form ax^2 + bx + c = 0 is equal to x = [-b +/-√(b^2 - 4ac)]/2a

with a = 2

       b = 11

       c = -63

substitute in the formula

x = [-11 +/- √(11^2 - 4(2)(-63))]2(2)

x = [-11 +/- √(121 + 504)]/4

x = [-11 +/- √625]/4

x = (-11 +/- 25)/4

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x2 = (-11 - 25)/4 = -36/4 = -9

since width can't be a negative number, x is 3.5

length = 2x + 11 = 2(3.5) + 11 = 18

7 0
2 years ago
I NEED HELP PLEASE, THANKS! :)
NISA [10]

Answer:   \bold{b)\quad \dfrac{2\pi}{3},\dfrac{4\pi}{3},0}

<u>Step-by-step explanation:</u>

Note the following identities: tan² x = sec²x - 1

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tan² x + sec x = 1

(sec² x -1) + sec x = 1

sec² x + sec x - 2 = 0

(sec x + 2)(sec x - 1) = 0

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sec x = -2          sec x = 1

\dfrac{1}{\cos x}=-2\qquad \dfrac{1}{\cos x}=1\\\\\cos x=-\dfrac{1}{2}\qquad \cos x=1\\\\x=\dfrac{2\pi}{3}, \dfrac{4\pi}{3}\qquad x=0

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