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ira [324]
3 years ago
8

Can we conclude that two similar figures can also be congruent figures? Explain.

Mathematics
1 answer:
shusha [124]3 years ago
7 0

Answer:

In similar figures, the angles are congruent, even if the sides are not. Notice that one angle in each pair of figures corresponds to an angle in the other figure. They have the same shape but not the same size

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Easy math for smart people problem: 7w-6=3(w+6)
LenKa [72]

Answer:

<h2>w=6</h2>

Step-by-step explanation:

7w-6=3w+18                     I expanded the bracket

+6 on both sides

7w=3w+24

-3w on both sides

4w=24

divide both sides by 4

w=6

5 0
2 years ago
Randy wants to use the Distributive Property to rewrite 56-21. Which expression could he use?
stiks02 [169]
B is your answer.
Because 7 times 8 is 56 and 7 times 3 is 21.
4 0
3 years ago
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if a and b are the measures of two first quadrant angles and sin a = 4/9 and sin b = 2/5 find sin (a+b)
Rzqust [24]
38/45. <span><span>49</span>+<span>25 </span></span><span>=<span>( 4 × 5) + (2 × 9) 9 × 5 </span></span><span>= <span>38/<span>45

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3 years ago
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Idk this plz help me
Alik [6]

Answer:

1. {12,0}

hope it helps.

5 0
2 years ago
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Every Thursday, Matt and Dave's Video Venture has “roll-the-dice" day. A customer may choose to roll two fair dice and rent a se
shepuryov [24]

Using the normal distribution, it is found that there is a 0.1357 = 13.57% probability that the total  amount paid for these second movies will exceed $15.00.

In a <em>normal distribution</em> with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

  • It measures how many standard deviations the measure is from the mean.  
  • After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
  • For n instances of a normal variable, the mean is n\mu and the standard error is s = \sigma\sqrt{n}

In this problem:

  • Mean of $0.47, standard deviation $0.15, hence \mu = 0.47, \sigma = 0.15
  • 30 instances, hence n\mu = 30(0.47) = 14.1, s = 0.15\sqrt{30} = 0.8216

The probability is <u>1 subtracted by the p-value of Z when X = 15</u>, hence:

Z = \frac{X - \mu}{\sigma}

Considering the n instances:

Z = \frac{X - n\mu}{s}

Z = \frac{15 - 14.1}{0.8216}

Z = 1.1

Z = 1.1 has a p-value of 0.8643.

1 - 0.8643 = 0.1357.

0.1357 = 13.57% probability that the total  amount paid for these second movies will exceed $15.00.

A similar problem is given at brainly.com/question/25769446

6 0
2 years ago
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