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Hitman42 [59]
3 years ago
6

What is the quotient of 237.6 and 33.

Mathematics
2 answers:
Rashid [163]3 years ago
6 0

Answer:

The quotient is 7.2.

Step-by-step explanation:

\frac{237.6}{33}  \\  =  \frac{237.6 \times 10}{33 \times 10} \\ = \frac{2376}{330}   \\ = \frac{2376 \div 33}{330 \div 33}  \\ =  \frac{72}{10}   \\ = 7.2

andrezito [222]3 years ago
5 0
7.2 would be the quotient, because 237.6 divided by 33 is 7.2 .
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I need help with 4 and 5 what are the answers?
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A university interested in tracking its honors program believes that the proportion of graduates with a GPA of 3.00 or below is
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Answer:

The value of the test statistic and its associated p-value at the 5% significance level are -1.54 and 0.9382, respectively.

Step-by-step explanation:

A university interested in tracking its honors program believes that the proportion of graduates with a GPA of 3.00 or below is less than 0.16.

This means that the null hypothesis is:

H_{0}: p \geq 0.16

Testing this hypothesis, means that the alternate hypothesis is:

H_{a}: p > 0.16

The test statistic is:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, \sigma is the standard deviation and n is the size of the sample.

0.16 is tested at the null hypothesis:

This means that \mu = 0.16, \sigma = \sqrt{0.16*0.84}

In a sample of 200 graduates, 24 students have a GPA of 3.00 or below.

This means that n = 200, X = \frac{24}{200} = 0.12

Value of the test statistic:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

z = \frac{0.12 - 0.16}{\frac{\sqrt{0.16*0.84}}{\sqrt{200}}}

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Pvalue:

The pvalue is the probability of finding a sample mean above 0.12, which is 1 subtracted by the pvalue of z = -1.54.

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1 - 0.0618 = 0.9382

The value of the test statistic and its associated p-value at the 5% significance level are -1.54 and 0.9382, respectively.

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