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tiny-mole [99]
3 years ago
9

What number is 30% of 80

Mathematics
2 answers:
IrinaVladis [17]3 years ago
8 0
The answer for 30% of 80 is “20”
hram777 [196]3 years ago
3 0

Answer:

24

Step-by-step explanation:

To find the % of something all you have to do is convert 30% to a decimal (.3) and times it by the number you want the percent out of (80) so 80 *.3= 24

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Which expression is equivalent to 18/14 × 4​
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Answer: 36/7

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Solve for t. You must write your answer in fully simplified form.<br> -19 = 7t
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-2.71

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A football is thrown from the top of the stands, 50 feet above the ground at an initial velocity of 62 ft/sec and at an angle of
Anvisha [2.4K]

a. i. The parametric equation for the horizontal movement is x = 43.84t

ii. The parametric equation for the vertical movement is y = 50 + 43.84t

b. the location of the football at its maximum height relative to the starting point is (60.1 ft, 60.1 ft)

<h2>a. Parametric equations</h2>

A parametric equation is an equation that defines a set of quantities a functions of one or more independent variables called parameters.

<h3>i. Parametric equation for the horizontal movement</h3>

The parametric equation for the horizontal movement is x = 43.84t

Since

  • the angle of elevation is Ф = 45° and
  • the initial velocity, v = 62 ft/s,

the horizontal component of the velocity is v' = vcosФ.

So, the horizontal distance the football moves in time, t is x = vcosФt

= vtcosФ

= 62tcos45°

= 62t × 0.7071

= 43.84t

So, the parametric equation for the horizontal movement is x = 43.84t

<h3>ii Parametric equation for the vertical movement</h3>

The parametric equation for the vertical movement is y = 50 + 43.84t

Also, since

  • the angle of elevation is Ф = 45° and
  • the initial velocity, v = 62 ft/s,

the vertical component of the velocity is v" = vsinФ.

Since the football is initially at a height of h = 50 feet, the vertical distance the football moves in time, t relative to the ground is y = 50 + vsinФt

= 50 + vtcosФ

= 50 + 62tsin45°

= 50 + 62t × 0.7071

= 50 + 43.84t

<h3>b. Location of football at maximum height relative to starting point</h3>

The location of the football at its maximum height relative to the starting point is (60.1 ft, 60.1 ft)

Since the football reaches maximum height at t = 1.37 s

The x coordinate of its location at maximum height is gotten by substituting t = 1.37 into x = 48.84t

So, x = 43.84t

x = 43.84 × 1.37

x = 60.0608

x ≅ 60.1 ft

The y coordinate of the football's location at maximum height relative to the ground is y = 50 + 48.84t

The y coordinate of the football's location at maximum height relative to the starting point is y - 50 = 48.84t

So,  y - 50 = 48.84t

y - 50 = 43.84 × 1.37

y - 50 = 60.0608

y - 50 ≅ 60.1 ft

So, the location of the football at its maximum height relative to the starting point is (60.1 ft, 60.1 ft)

Learn ore about parametric equations here:

brainly.com/question/8674159

5 0
2 years ago
Explain how to answer the question attached
LenaWriter [7]

Answer:

The players ran 150 meters

Step-by-step explanation:

Pythagorean Theorem: a² + b² = c²

Since we have a rectangle with sides 90 and 120, we know if we split a diagonal across it, we will get a right triangle with legs 90 and 120. From there, we use Pythagorean Theorem to solve:

90² + 120² = c²

8100 + 14400 = c²

c² = 22500

√c² =  √22500

c = 150

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(a) Christine received 70 dollars.<br> Write a signed number to represent this change.
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70 or +70
To represent a positive integer
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