Step-by-step explanation:
Start by finding (fog)(x)
To find this function, substitute x=
x−1
4
That is g(x) into f(x)
⇒(f∘g)(x)=(
x−1
4
)
2
−2(
x−1
4
)+5
=
(x−1)
2
16
−
x−1
8
+5
Now substitute x=3
⇒(f∘g)(3)=
(3−1)
2
16
−
3−1
8
+5
=
4
16
−
2
8
+5=4−4+5=5.
Hope it helps:)
The standard form of a quadratic equation is

, while the vertex form is:

, where (h, k) is the vertex of the parabola.
What we want is to write

as

First, we note that all the three terms have a factor of 3, so we factorize it and write:

.
Second, we notice that

are the terms produced by

, without the 9. So we can write:

, and substituting in

we have:
![\displaystyle{ y=3(x^2-6x-2)=3[(x-3)^2-9-2]=3[(x-3)^2-11]](https://tex.z-dn.net/?f=%5Cdisplaystyle%7B%20y%3D3%28x%5E2-6x-2%29%3D3%5B%28x-3%29%5E2-9-2%5D%3D3%5B%28x-3%29%5E2-11%5D)
.
Finally, distributing 3 over the two terms in the brackets we have:
![y=3[x-3]^2-33](https://tex.z-dn.net/?f=y%3D3%5Bx-3%5D%5E2-33)
.
Answer:
The given study is observational study
To gauge how strongly two variables are related to one another, correlation coefficients are used.
A statistical indicator of the strength of the association between the relative movements of two variables is the correlation coefficient. The values are in the -1.0 to 1.0 range. There was a measurement error in the correlation if the estimated value was larger than 1.0 or lower than -1.0. Perfect negative correlation is shown by a correlation of -1.0, and perfect positive correlation is shown by a correlation of 1.0. A correlation of 0.0 indicates that there is no linear link between the two variables' movements. Finance and investing can benefit from the usage of correlation statistics.
To know more about statistic indicator
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Answer:
1. X is added to 8
2. Subtract 14 by a number
3. Multiply 2 after you add 3 into a number.
4.. Twice a number plus 3
5. Divide 15 by a number
Step-by-step explanation: