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Lyrx [107]
3 years ago
7

Ill give brainliest help me out

Mathematics
1 answer:
dusya [7]3 years ago
5 0

Answer:

A

Step-by-step explanation:

In the graphing calculator, I tried out the different answers, and I think this graph matches yours pretty closely. x is multiplied by a number greater than one, and it looks like instead of expanding/stretching open, it folded in more, which is compressing.

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A variable expression consists only of numbers <br><br> A. True<br><br> B. False
insens350 [35]

False, an expression can have letters too.

5 0
3 years ago
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In math what is the answer to this question. -27•7/9=
agasfer [191]
-27 \times \frac{7}{9} = -3\times \frac{7}{1} = -3\times 7 = \boxed{-21}

Your answer is -21
6 0
3 years ago
Joe brought 17 packs of cola to a party, and each pack had 8 cans. Teresa brought 6 cans of juice. How many cans did they bring
KATRIN_1 [288]

Answer:

Hello!!

If Joe brought 17 packs of cola to a party, and each pack had 8 cans. Teresa brought 6 cans of juice. They brought 142 cans in all.

Step-by-step explanation:

17×8=136

136+6=142

Hope this helps!!

6 0
3 years ago
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WHAT IS THE VALUE IF X???‼️‼️ HELP ASAP
MaRussiya [10]

The value of x is 40.

Solution:

Given ΔVDG and ΔVNG are similar triangles.

DG = 207, NQ = 138, GQ = 60, QV = x

To find the value of x.

In two triangles are similar, then the measures of the corresponding sides are in proportional to each other.

$\Rightarrow\frac{DG}{NQ}=\frac{GQ}{QV}

Substitute the given values.

$ \Rightarrow\frac{207}{138}=\frac{60}{x}

Do cross multiplication, we get

$ \Rightarrow{207\times x}=138\times60

$ \Rightarrow{207\times x}=8280

Divide by 207 on both sides of the equation, we get

$ \Rightarrow x=\frac{8280}{207}

$ \Rightarrow x=40

Hence the value of x is 40.

3 0
3 years ago
What is the approximate distance between the points (-5,1) and (-2,3) on a coordinate grid? Show me an example please
yaroslaw [1]

Answer:

d=\sqrt{13}\ units   or  d=3.61\ units

Step-by-step explanation:

we know that

the formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

A(-5,1)\\E(-2,3)  

substitute the values

d=\sqrt{(3-1)^{2}+(-2+5)^{2}}

d=\sqrt{(2)^{2}+(3)^{2}}

d=\sqrt{13}\ units

d=3.61\ units

the graph in the attached figure  

4 0
3 years ago
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