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3 years ago

!!!!!!!!!!!!!!!!!! Help!!!

Mathematics

1 answer:

kipiarov [429]3 years ago

8 0

5. The value is 10,000.

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Help please V/5 = 3/7 v=

Serggg [28]

Answer:

v = 15/7, or 2.14

Step-by-step explanation:

Find a common denominator, or multiply both denominators by each other, and well as the numerator.

v/5 = 3/7 can be written as 7v/35 = 15/35

multiplying both sides with 35, we are left with 7v = 15

v = 15/7, or 2.14

8 0

3 years ago

Read 2 more answers

X-y-2z=4 -x+2y+z=1 -x+y-3z=11

juin [17]

Answer:

look at the picture above

6 0

3 years ago

a rectangle has a length of 15 inches less than 5 times it’s width. If the area of the rectangle is 2750 square inches. what is

irakobra [83]

let L = length and let W = width.

Use the equations 2L + 2W = 2750

and L = 5W + 15

Then do the steps as follows -

1. Plug the equation for what L equals into the first equation

2(5W+15) + 2W = 2750

2. Then distribute the 2

10W + 30 + 2W = 2750

3. Then add like terms

12W + 30 = 2750

4. Then subtract 30 from both sides

12W = 2720

5. Divide by 12 on both sides

W = 226.67

6. Then plug that into the second equation

L = 5(226.67) + 15

L = 1148.35 should be the answer

4 0

3 years ago

What do race car drivers like to do?: 3y-6+7y-4y

stich3 [128]

3y + 7y = 11y - 4y = 7y -6

Answer: 7y - 6

:) I think this may be correct

4 0

3 years ago

5. A yacht is cruising at 20 knots at bearing of 185° when a 15 knot wind starts to blow at a bearing of 290°. Find the directio

kicyunya [14]

Answer:

Direction of the boat is 43.05° and the speed is 21.66 knot

Step-by-step explanation:

yacht speed = 20 knots

yacht bearing = 185° = 85° below the negative horizontal x-axis

wind speed = 15 knots

wind bearing = 290° = 20° above the negative horizontal x-axis

we find the x and y components of the boat velocities

for yacht,

x component = -20 cos 85° = -1.74 knots

y component = -20 sin 85° = -19.92 knots

for the wind,

x component = -15 cos 20° = -14.09 knots

y component = 15 sin 20° = 5.13 knots

total x component Vx = -1.74 + (-14.09) = -15.83 knots

total y component Vy = -19.92 + 5.13 = -14.79 knots

Resultant speed of the boat = $\sqrt{Vx^{2} + Vy^{2} }$

==> $\sqrt{15.83^{2} + 14.79^{2} }$ = 21.66 knot

direction of boat = $tan^{-1} \frac{Vy}{Vx}$

==> $tan^{-1} \frac{14.79}{15.83}$ = 43.05°

3 0

4 years ago