H=2f/m+1
subtract one from both sides
h-1=2f/m
multiply m to both sides
m*h-1=2f
divide 2 both sides
mh-1/2=F
<span>(the whole left side of the equation is divided by 2 i just cant do it on the computer)</span>
The center-radius form<span> of the </span>circle<span> equation is in the format (x – h)</span>2<span> + (y – k)</span>2<span> = r</span>2<span>, with the center being at the point (h, k) and the radius being "r". Therefore, the center is located at point (1, -3) and is located in the fourth quadrant, last option. Hope this answers the question.</span>
Answer:
20
Step-by-step explanation:
Divide 4 by 1/5 in decimal form, 1/5 in decimal form is 0.20. You can get the decimal form by dividing 1 by 5.
So 4/0.20 = 20.
Answer by CubeyThePenguin(3113) (Show Source): You can put this solution on YOUR website!
x = 5y
xy = 320
Substitute the first equation into the second equation
(5y)(y) = 320
5y^2 = 320
y^2 = 64
y = 8 (y must be positive)
The integers are (x, y) = (40, 8).
