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Dovator [93]
3 years ago
7

Simply the product -7x/5y * 5x/-7

Mathematics
2 answers:
slava [35]3 years ago
6 0
<span>-7x/5y * 5x/-7
= x^2/y

(-) times(-) = positive
and canceled out 7, 5 
so answer is
</span>x^2/y
ch4aika [34]3 years ago
5 0
We are asked to simplify the expression \frac{-7x}{5y} \cdot  \frac{5x}{-7}, 

what we do is, we form a single fraction where the numerator is the product of the numerators, and the denominator is the product of the denominators, that is:

\frac{-7x}{5y} \cdot \frac{5x}{-7}= \frac{-7\cdot5 \cdot x \cdot x}{5 \cdot(-7) \cdot y}

simplify the common numbers and terms in the numerator and denominator:

\frac{-7\cdot5 \cdot x \cdot x}{5 \cdot(-7) \cdot y}=\frac{5 \cdot x \cdot x}{5  \cdot y}=\frac{x \cdot x}{y}= \frac{ x^{2} }{y}


Answer: \frac{ x^{2} }{y}

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We know that any function y= f(x) will become y=k f(x) after dilation of k units on the x, where k= scale factor for dilation.

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On a coordinate plane, parallelogram H I J K is shown. Point H is at (negative 2, 2), point I is at (4, 3), point J is at (4, ne
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HIJK is a parallelogram because the midpoint of both diagonals is

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Step-by-step explanation:

If (x , y) is the mid-point of a segment whose end points are (x_{1},y_{1})  and  (x_{2},y_{2})  then,

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In a parallelogram, its diagonals intersect each other at their mid-points

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∵ HIJK is a quadrilateral

∵ HJ and IK are its diagonals

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∵ J = (4 , -2)

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∵ M_{HJ}=(\frac{-2+4}{2},\frac{2+-2}{2})

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∴ M_{HJ}=(1,0)

∴ The mid-point of HJ is (1 , 0)

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∴ M_{IK}=(\frac{2}{2},\frac{0}{2})

∴ M_{IK}=(1,0)

∴ The mid-point of IK is (1 , 0)

∵ The mid-points of HJ and IK are equal

∴ HJ and IK bisects each other

∴ HIJK is a parallelogram because its diagonals bisect each other

HIJK is a parallelogram because the midpoint of both diagonals is

(1 , 0), which means the diagonals bisect each other

Learn more:

You can learn more about parallelogram in brainly.com/question/6779145

#LearnwithBrainly

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