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Dovator [93]
3 years ago
7

Simply the product -7x/5y * 5x/-7

Mathematics
2 answers:
slava [35]3 years ago
6 0
<span>-7x/5y * 5x/-7
= x^2/y

(-) times(-) = positive
and canceled out 7, 5 
so answer is
</span>x^2/y
ch4aika [34]3 years ago
5 0
We are asked to simplify the expression \frac{-7x}{5y} \cdot  \frac{5x}{-7}, 

what we do is, we form a single fraction where the numerator is the product of the numerators, and the denominator is the product of the denominators, that is:

\frac{-7x}{5y} \cdot \frac{5x}{-7}= \frac{-7\cdot5 \cdot x \cdot x}{5 \cdot(-7) \cdot y}

simplify the common numbers and terms in the numerator and denominator:

\frac{-7\cdot5 \cdot x \cdot x}{5 \cdot(-7) \cdot y}=\frac{5 \cdot x \cdot x}{5  \cdot y}=\frac{x \cdot x}{y}= \frac{ x^{2} }{y}


Answer: \frac{ x^{2} }{y}

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Use the distance formula to determine whether ABCD below is a parallelogram. A(-3,2) B(-3,3) C (5,-3) D (-1.-5)
Pani-rosa [81]

Answer:

ABCD is not a parallelogram

Step-by-step explanation:

Use the distance formula to determine whether ABCD below is a parallelogram. A(-3,2) B(-3,3) C (5,-3) D (-1.-5)

We have to find the length of the sides of the parallelogram using the formula below

= √(x2 - x1)² + (y2 - y1)² when given vertices (x1, y1) and (x2, y2)

For side AB

A(-3,2) B(-3,3)

= √(-3 -(-3))² + (3 -2)²

= √0² + 1²

= √1

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For side BC

B(-3,3) C (5,-3)

= √(5 -(-3))² + (-3 -3)²

= √8² + -6²

= √64 + 36

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For side CD

C (5,-3) D (-1.-5)

= √(-1 - 5)² + (-5 - (-3))²

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For sides AD

A(-3,2) D (-1.-5)

= √(-1 - (-3))² + (-5 -2)²

= √(2² + -7²)

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= √53 units

A parallelogram is a quadrilateral with it's opposite sides equal

From the above calculation

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3 0
3 years ago
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garri49 [273]

Answer:

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y=mx+b.

For this particular line, you would write:

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