With any equation you are allowed to take the logarithm of both sides so
5^c=125 now take the logarithm base 5 to both sides giving.
log5(5^c)=log5(125), using the rule log(a^b)=a*log(b) you get
c log5(5)=log5(125), since log5(5)=1
c=log5(125)
Answer:
1
Step-by-step explanation:
The product of any nonzero real number and its multiplicative inverse (reciprocal) is always 1. This is called the multiplicative identity or the identity element of multiplication.
~Hope this helps!~
Answer:
Step-by-step explanation:
Begin with substuting the x variable with -2, we do this because the question has listed the value of x already.
Using the value of x, -2 we determine g(x).
g(x) = -2^2 + 2
Above is what the equation would look as, after you input the value of -2.
Using pemdas, (parantheses, exponents, multiplication, division, addition, subtraction) solve the equation.
-2^2 = 4
Think of it as -2 * -2, which is why -2^2 is 4.
Add 4 +2.
4 + 2 = 6.
Therefore, the value of g(x) = 6
5 obtuse no acute and no right
Answer:
Step-by-step explanation:
<u>Answer choices:</u>
A) Asher made errors in multiplication.
- No, the products are correct
B) Asher found multiples of 10, not factors of 10.
C) Asher should have multiplied 10 × 4 as well.
- No, 4 is not one of the factors of 10
D) Asher should have gotten this as the answer: 1, 2, 5, and 10.
- Yes, these are the true factors of 10
E) Asher should have gotten this as the answer: 10, 20, 30, 40, …
- No, the correct one is one before
