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3 years ago

NEED HELP, WILL GIVE 98 POINTS

Mathematics

2 answers:

Taya2010 [7]3 years ago

7 0

I am confusion, but sure lol

enot [183]3 years ago

4 0

1)C

2)AD

3)CD

i hope this helps chu

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What is x in this equation- 3/2x-7=-11

Sunny_sXe [5.5K]

3/2x-7=-11

We move all terms to the left:

3/2x-7-(-11)=0

Domain of the equation: 2x!=0

x!=0/2

x!=0

x∈R

We add all the numbers together, and all the variables

3/2x+4=0

We multiply all the terms by the denominator

4*2x+3=0

Wy multiply elements

8x+3=0

We move all terms containing x to the left, all other terms to the right

8x=-3

x=-3/8

3 0

3 years ago

Write a simplified polynomial expression in standard form to represent the area of the rectangle below.

motikmotik

(5x+2)(x-4
5x (x)+2(x)+5x (-4)+2 (-4)
5x^2+2x-20x-8
5x^2-18x-8
C. 5x^2-18x-8

3 0

3 years ago

Read 2 more answers

What is the average rate of change of the table below using the interval [‒2, 0]?

Scilla [17]

Answer:

-2x

Step-by-step explanation:

3 0

3 years ago

Show work please<br> \sqrt(x+12)-\sqrt(2x+1)=1

Nesterboy [21]

Answer:

$x=4$

Step-by-step explanation:

Given $\displaystyle\\\sqrt{x+12}-\sqrt{2x+1}=1$ , start by squaring both sides to work towards isolating $x$ :

$\displaystyle\\\left(\sqrt{x+12}-\sqrt{2x+1}\right)^2=\left(1\right)^2$

Recall $(a-b)^2=a^2-2ab+b^2$ and $\sqrt{a}\cdot \sqrt{b}=\sqrt{a\cdot b}$ :

$\displaystyle\\\left(\sqrt{x+12}-\sqrt{2x+1}\right)^2=\left(1\right)^2\\\implies x+12-2\sqrt{(x+12)(2x+1)}+2x+1=1$

Isolate the radical:

$\displaystyle\\x+12-2\sqrt{(x+12)(2x+1)}+2x+1=1\\\implies -2\sqrt{(x+12)(2x+1)}=-3x-12\\\implies \sqrt{(x+12)(2x+1)}=\frac{-3x-12}{-2}$

Square both sides:

$\displaystyle\\(x+12)(2x+1)=\left(\frac{-3x-12}{-2}\right)^2$

Expand using FOIL and $(a+b)^2=a^2+2ab+b^2$ :

$\displaystyle\\2x^2+25x+12=\frac{9}{4}x^2+18x+36$

Move everything to one side to get a quadratic:

$\displaystyle-\frac{1}{4}x^2+7x-24=0$

Solving using the quadratic formula:

A quadratic in $ax^2+bx+c$ has real solutions $\displaystyle x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$ . In $\displaystyle-\frac{1}{4}x^2+7x-24$ , assign values:

$\displaystyle \\a=-\frac{1}{4}\\b=7\\c=-24$

Solving yields:

$\displaystyle\\x=\frac{-7\pm \sqrt{7^2-4\left(-\frac{1}{4}\right)\left(-24\right)}}{2\left(-\frac{1}{4}\right)}\\\\x=\frac{-7\pm \sqrt{25}}{-\frac{1}{2}}\\\\\begin{cases}x=\frac{-7+5}{-0.5}=\frac{-2}{-0.5}=\boxed{4}\\x=\frac{-7-5}{-0.5}=\frac{-12}{-0.5}=24 \:(\text{Extraneous})\end{cases}$