Answer:
Step-by-step explanation:
The opposite angles in a quadrilateral theorem states that when a quadrilateral is inscribed in a circle, the angles that are opposite each other are supplementary, their degree measures add up to 180 degrees. One can apply this here by using the sum of (<C) and (<A) to find the measure of the parameter (z). Then one can substitute in the value of (z) to find the measure of (<B). Finally, one can use the opposite angles in a quadrilateral theorem to find the measure of angle (<D) by using the sum of (<B) and (D).
Use the opposite angles in an inscribed quadrialteral theorem,
<A + <C = 180
Substitute,
14x - 7 + 8z = 180
Simplify,
22z - 7 = 180
Inverse operations,
22z = 187
z = 
Simplify,
z = 
Now substitute the value of (z) into the expression given for the measure of angle (<B)
<B = 10z
<B = 10()
Simplify,
<B = 85
Use the opposite angles in an inscribed quadrilateral theorem to find the measure of (<D)
<B + <D = 180
Substitute,
85 + <D = 180
Inverse operations,
<D = 95
Answer:
the file is 20 kb
Step-by-step explanation:
16kb/80%
xkb/100%
1600=80%
80 80
20KB
Answer:
(a) yes
(b) no; see below
Step-by-step explanation:
(a) Integer roots of the quartic will be integer divisors of 6. One of the divisors of 6 is 3, so 3 is a possible root.
(b) In order for 3 to be a double root, it would have to be a double factor of 6. The only integer factors of 6 are 1, 2, 3, 6. (3² = 9 is not one.)
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The quartic can be written as ...
k(x -a)(x -b)(x -c)(x -d) . . . . . where a, b, c, d, k are integers
The constant term will be kabcd, of which each of the roots is a factor. If the constant is 6 and one root is d=3, then we must have
kabcd = 3kabc = 6
kabc = 6/3 = 2
Among these four integer factors, there must be an even number of minus signs, and one that has the value ±2. Another root whose value is 3 will not satisfy the requirements.
so you can not make the number smaller or reduce the fraction
ex.u can not simplify 11 over 12 because 11 is a prime number
Answer:
Quadratic
Step-by-step explanation:
This is a quadratic equation because it's in the form of y=ax^2+bx+c
If it were linear, the graph would be a straight line and wouldn't contain a second degree term
If it were exponential there would be a growth or decay factor
