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lapo4ka [179]
3 years ago
8

Over millions of years silt washed into a lake formed layers of sedimentary rock. What type of rock was likely formedscien​

Biology
1 answer:
morpeh [17]3 years ago
6 0
Formedscien I think
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Selection is:
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Answer:

Making more babies that will survive and having an adaption

Explanation:

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What is the best explanation for a BbCc x bbcc cross producing offspring in a 5:5:1:1 phenotypic ratio
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Answer:

These genes are linked.

Explanation:    

You will find the complete answer and explanation in the attached file due to technical problems.

Download pdf
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critically evaluate the role of a persons rights and responsibilities when executing freedom of expression during verbal interpe
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A person does have basic human rights and one is the freedom of expression. Though this is the case, we should understand that our right to freely express ourselves (from political to religious views), it does not necessarily give us the right to impede another person’s. A play with words can easily hurt or even harass other people, and in return may be a form of human right violation. 

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3 years ago
4) A homozygous groucho fly ( gro, bristles clumped above the eyes) is crossed with a homozygous rough fly (ro, eye abnormality)
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Answer and Explanation:

  • A homozygous groucho fly ( gro, bristles clumped above the eyes) is crossed with a homozygous rough fly (ro, eye abnormality).
  • The F1 females are testcrossed, producing these offspring: groucho 518 rough 471 groucho, rough 6 wild-type 5 1000 a) What is the linkage distance between the two genes? B) Plot the genes on a map c) If the genes were unlinked and the F1 females were mated with the F1 males, what would be the offspring in the F2 generation?

1st cross:

Parental) grogro ro+ro+ x  gro+gro+ roro

F1) gro+gro ro+ro

2nd cross:

Parental)  gro+gro ro+ro   x  grogro roro

Gametes) gro+ro+                       gro ro

                gro+ro                         gro ro

                gro ro+                        gro ro

                gro ro                          gro ro

Punnet square)  

                   gro+ro+             gro+ro              gro ro+            gro ro  

gro ro    gro+gro ro+ro   gro+gro roro    grogro ro+ro    grogro roro

gro ro    gro+gro ro+ro   gro+gro roro    grogro ro+ro    grogro roro

gro ro    gro+gro ro+ro   gro+gro roro    grogro ro+ro    grogro roro

gro ro    gro+gro ro+ro   gro+gro roro    grogro ro+ro    grogro roro

F2)

0.518 grogro ro+ro (518 individuals)

0.471 gro+gro roro (471 individuals)

0.006 grogro roro (6 individuals)

0.005 gro+gro ro+ro (5 individuals)

Total number of individuals 1000

<u><em>Note</em></u>: These frequencies were calculated dividing the number of individuals belonging to each genotype by the total number of individuals in the F2.

To know if two genes are linked, we must observe the progeny distribution. <em>If individuals, whos </em><em>genes assort independently,</em><em> are test crossed, they produce a progeny with equal </em><em>phenotypic frequencies 1:1:1:1</em>. <em>If</em> we observe a <em>different distribution</em>, that is that <em>phenotypes appear in different proportions</em>, we can assume that<em> genes are linked in the double heterozygote parent</em>.  

In the exposed example we might verify which are the recombinant gametes produced by the F1 di-hybrid, and we can recognize them by looking at the phenotypes with lower frequencies in the progeny.  

By performing this cross we know that the phenotypes with lower frequencies in the progeny are groucho, rough and wild-type. So the recombinant gametes are <em>gro+ro+</em> and <em>gro ro</em>, while the parental gametes are <em>gro+ro</em> and <em>gro ro+.</em>

So, the genotype, in linked gene format, of the double heterozygote individual in the <u>F1</u> is gro+ro/gro ro+.

To calculate the recombination frequency we will make use of the next formula: P = Recombinant number / Total of individuals. The genetic distance will result from multiplying that frequency by 100 and expressing it in map units (MU). One centiMorgan (cM) equals one map unit (MU).

The map unit is the distance between the pair of genes for which one of every 100 meiotic products results in a recombinant product.

The recombination frequency is:

P = Recombinant number / Total of individuals

P = 6 + 5 / 1000

P = 11 / 1000

P = 0.011

The <u>genetic distance between genes,</u> is 0.011 x 100= 1.1 MU.

<u>Genetic Linkage Map:</u>

Parental Phenotypes)  

-----gro+------ro----              -----gro------ro+----

----- gro ------ro----               ---- gro------ ro ----

Recombinant phenotypes)

-----gro+------ro+----              -----gro------ro----

----- gro ------ ro----                -----gro------ro----

<u>If the genes were unlinked</u> and the F1 females were mated with the F1 males, the offspring in the F2 generation would have been

4/16 = 1/4 gro+gro ro+ro  

4/16 = 1/4 gro+gro roro  

4/16 = 1/4 grogro ro+ro    

4/16 = 1/4 grogro roro

Their phenotypic frequencies would be 1:1:1:1 related.                                                  

7 0
3 years ago
The students decide to model how the motion of two plates occurs. Which statement best describes the ability of the model to pre
Eddi Din [679]

Explanation:

In my view, all factors are equally responsible for this.

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