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3 years ago

15

rasheed needs to save $231 to earn money he plans to wash cars and charge $12 per car write to estimates rasheed could use to de

termine how many cars he needs to wash

1 answer:

prisoha [69]3 years ago

6 0

He would have to wash 20 cars at first i got 19.25 because i divided 231 by 12 but i rounded up to 20 just to be safe....

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Convert 312 quarts to gallons.

dimaraw [331]

78 gallons is the same as 312 quarts

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3 years ago

Which could be the first step in simplifying this expression? Check all that apply. (x cubed x Superscript negative 6 Baseline)

PtichkaEL [24]

Answer:

$(x^{-3} )^{2}$

$x^6 x^{-12}$

Step-by-step explanation:

$(x^{3} x^{-6} )^{2}$ is the expression given to be solved.

First of all let us have a look at <u>3 formulas</u>:

$1.\ p^a \times p^b = p^{(a+b)}\\2.\ (p^a \times q^b)^c = (p^{a})^c \times (q^{b})^c\\3.\ (p^a)^b = p^{a\times b}$

Both the formula can be applied to the expression( $(x^{3} x^{-6} )^{2}$ ) during the first step while solving it.

<u>Applying formula (1):</u>

$(x^{3} x^{-6} )^{2}$

Comparing the terms of $(x^{3} x^{-6} )$ with $p^a \times p^b$

$p=x, a =3, b=-6$

$\Rightarrow x^{3+(-6)}\\\Rightarrow x^{3-6}\\\Rightarrow x^{-3}$

So, $(x^{3} x^{-6} )^{2}$ is reduced to $(x^{-3} )^{2}$

<u>Applying formula (2):</u>

Comparing the terms of $(x^{3} x^{-6} )^{2}$ with $(p^a \times q^b)^c$

$p=q=x, a =3, b=-6, c=2$

$\Rightarrow (x^{3})^2\times (x^{-6})^2\\\text{Applying Formula (3)}\\x^6 x^{-12}$

So, $(x^{3} x^{-6} )^{2}$ is reduced to $x^6 x^{-12}$ .

So, the answers can be:

$(x^{-3} )^{2}$

$x^6 x^{-12}$

8 0

2 years ago

If Pam can install 12 insulators in 15 hours, how long does it take to install one insulator

Xelga [282]

The time it takes to install 1 insulator would be 1.25 hours

7 0

3 years ago

Read 2 more answers

4 ^-3 rewrite without an exponent

hichkok12 [17]

Answer:

(1/4)³

Step-by-step explanation:

Hope it helps you

5 0

2 years ago

Read 2 more answers

Find the following when a = -1, b = 2, c = -1/4<br> (4b - 3)/(2a) -1

Katena32 [7]

We substitute the given into the equation
given: a=-1, b=2, c= $\frac{-1}{4}$
=( $\frac{4b-3}{2a}$ -1
= $\frac{4(2)-3}{2(-1)}$ -1
= $\frac{8-3}{-2}$ -1
= $\frac{5}{-2}$ -1
to continue, we can either find a common denominator or change the fraction to decimal.
Fraction to Decimal:
$\frac{5}{-2}$ =-2.5
Equation=-2.5-1=-3.5
OR Common Denominator:
= $\frac{5}{-2}$ $\frac{-1}{1}$ × $\frac{-2}{-2}$ (denominator should be -2=common)
= $\frac{5}{-2}$ + $\frac{2}{-2}$
= $\frac{7}{-2}$
which also = to -3.5

3 0

3 years ago