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Tanya [424]
3 years ago
12

Can somebody please help me with 11 and 17

Mathematics
1 answer:
Nookie1986 [14]3 years ago
3 0
11.\\2p+5r=q\ \ \ \ |subtract\ 5r\ from\ both\ sides\\\\2p=q-5r\ \ \ \ |divide\ both\ sides\ by\ 2\\\\\boxed{p=\dfrac{q-5r}{2}}


17.\\\dfrac{2}{5}(z+1)=y\ \ \ \ |multiply\ both\ sides\ by\ \dfrac{5}{2}\\\\z+1=\dfrac{5}{2}y\ \ \ \ |subtract\ 1\ from\ both\ sides\\\\\boxed{z=\frac{5}{2}y-1}
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Solve each proportion 3/39= y/13
Sphinxa [80]

Answer:

y = 1

Step-by-step explanation:

\frac{3}{39}  =  \frac{y}{13}

Cross multiply

39 = 39y

Divide by 39

y = 1

6 0
3 years ago
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D+g/h for d =29, for g=16,h=9
dsp73

Answer: 31  and 1/9

Step-by-step explanation:

d =29, for g=16,h=9

replace values of each number in equati/on:

d+g/h=29+19/9=(9*29+19)/9=( 261+19)/9=280/9= 31 and 1/9

8 0
4 years ago
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Write the equation of the line perpendicular to y= 2/5x+6/6 that passes through the point (-2,6)
Oliga [24]
The line to find: y = mx + b
the line perpendicular to y= 2/5x+6/6 so it has the slope m × 2/5 = -1
thus the slope m = -5/2
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the equation of the line is y = -5/2x +1
3 0
4 years ago
F(x)= x^2– 3x + 9<br> g(x) = 3x^3+ 2x^2– 4x – 9<br> Find (f - g)(x).
denis-greek [22]

Answer:

\large \boxed{\sf \ \ -3x^3-x^2+x+18 \ \ }

Step-by-step explanation:

Hello, please consider the following.

(f-g)(x)=f(x)-g(x)=x^2-3x+9-(3x^3+2x^2-4x-9)\\\\=x^2-3x+9-3x^3-2x^2+4x+9\\\\=\boxed{-3x^3-x^2+x+18}

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

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3 years ago
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Sorry don’t now the answer to this problem
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