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Vikki [24]
3 years ago
6

The mean weight of the packages Joan shipped was 2.5 pounds. If Joan mailed four packages and three of them had weights of 1.8,

3.2 and 2.7 pounds, then what did the other package weigh?
2.8
2.3
3.3
Mathematics
2 answers:
victus00 [196]3 years ago
5 0
The right answer is 2.3
mrs_skeptik [129]3 years ago
3 0

Answer:

2.3 is the answer

Step-by-step explanation:

Name the unknown package n

[1.8 + 3.2 + 2.7 + n]/4 = 2.5

[7.7 + n] = 2.5 × 4

7.7 + n = 10

n = 10 - 7.7

n = 2.3

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The number 8,844 contains two sets of digits in which one digit is 10 times as great as the other. Find the values of the digits
Alecsey [184]
<span>The first 8 (in the thousands location) has a value of 8,000 while the second 8 (in the hundreds place) is valued at 800. Similarly, the first 4 (in the tens location) has a value of 40 while the 4 in the units position is simply valued at 4.</span>
5 0
3 years ago
I’ll give Brainly! Jim has ten more dollars than Gail. Together they have at most twenty-seven dollars.
jeyben [28]

Answer:

see below

Step-by-step explanation:

Let g= amount that gail has

j = g+10

j+g ≤ 27

Substitute  the first equation into the inequality

g+g+10 ≤ 27

2g + 10 ≤ 27

Subtract 10 from each side

2g≤ 17

Divide by 2

g≤ 8.5

3 0
4 years ago
Read 2 more answers
At the souvenir shop. Theo buys k key chains and p photo frames
stealth61 [152]

Answer:

Total cost of Theo's purchases in terms of k and p=2.49(k + p) + 5.99

Step-by-step explanation:

Cost of k key chain=$2.49

Cost of p photo frames=$2.49

Cost of a T-shirt=$5.99

Total cost of all items=cost of k key chain + cost of p photo frame + cost of The shirt

=2.49k + 2.49p + 5.99

Factorise

2.49 is common to both k and p

=2.49(k + p) + 5.99

Total cost of Theo's purchases in terms of k and p=2.49(k + p) + 5.99

4 0
3 years ago
B) 6x(x - 2y) + 5y(x – 2y)​
Tcecarenko [31]

answer:

6x(x - 2y) + 5y(x – 2y)​

= 6x^2 - 12xy + 5xy - 10y^2

= 6x^2 - 7xy - 10y^2

7 0
3 years ago
A bucket that weighs 4 lb and a rope of negligible weight are used to draw water from a well that is 90 ft deep. The bucket is f
Misha Larkins [42]
<span>The work on the bucket is a function of height--->h 
dwork = F(h)*dh 
dwork = weight(h)*dh 

weight(t) = 44 - 0.2t 
but t = h/v 
weight(h) = 44 - 0.2(h/v) --->[44 - 8] = 36 lbs at top 

work = ∫ weight(h) * dh 
work = ∫[44 - 0.2(h/v)] dh <0 to 80>ft 
work = ∫[44 - 0.1h] dh <0 to 80>ft 

work = 44h - 0.1*0.5*h^2 <0 to 80>ft 
work = 44*80 - (0.1*0.5*80^2) = 3200 ft-lbs</span><span>

</span>
6 0
4 years ago
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