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Maksim231197 [3]
3 years ago
9

Jim uses the function f(x) = 0.7x + 23 to determine the amount he charges for each used

Mathematics
2 answers:
Neporo4naja [7]3 years ago
6 0
Each used drone is sold at a cost of f(x) = 0.7x + 23 dollars. A customer also has to pay 8% sales tax on that cost. The function g(x) = 1.08x gives us the final cost of a used drone including the tax. So we'll apply the g(x) upon the f(x) to get the final cost for each drone. It would be

g(f(x)) = 1.08(0.7x + 23)
= 0.756x + 24.84

So the answer is h(x) = 0.756x + 24.84
sertanlavr [38]3 years ago
3 0

Answer: Our required function be

0.756x+24.84

Step-by-step explanation:

Since we have given that

f(x)=0.7x+23

where x is the original value of the drone.

So, g(x)=1.08x

the above function is used to determine the amount a customer pays for a drone at Jim's store including 8% sales tax.

So, we will find a function to determine the total amount a customer pays for a used drone at Jim's store including 8% sales tax.

gof(x)=g(f(x))=1.08(0.7x+23)\\\\g(f(x))=0.756x+24.84

Hence, our required function be

0.756x+24.84

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The first five terms of a pattern are shown.
Andrej [43]

Answer:

C

Step-by-step explanation:

There is a common ratio between consecutive term in the sequence, that is

\frac{3}{10} ÷ \frac{3}{100} = 3 ÷ \frac{3}{10} = 30 ÷ 3 = 300 ÷ 30 = 10

This indicates the sequence is geometric with n th term

a_{n} = a(r)^{n-1}

where a is the first term and r the common ratio

Here a = \frac{3}{100} and r = 10 , thus

a_{n} = \frac{3}{100} (10)^{n-1}

    = \frac{3}{10^{2} } × 10^{n-1}

    = 3 × 10^{-2} × 10^{n-1}

    = 3 × 10^{n-3}

Thus

a_{n} = 3(10)^{n-3} → C

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4 years ago
Me dicen la sifra 5p-14=8p+19
Alex
5p-14=8p+19
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3 years ago
Need help with this question asap!!
Juli2301 [7.4K]

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Answer:

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Step-by-step explanation:

Given,\\\\In\ 1\ hour\ lawn\ can\ be\ mowed= 3000\ yd^2\\\\we\ know\ that\\\\1\ Hour=60\ minutes\\\\In\ 60\ minutes\ lawn\ can\ be\ mowed=3000\ yd^2\\\\In\ 1\ minute\ lawn\ can\ be\ mowed=\frac{3000}{60}\ yd^2\\\\In\ 1\ minute\ lawn\ can\ be\ moved=50\ yd^2

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