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3 years ago

What is the slope of the line passing through the points (2, 1) and (4, 31)?

Mathematics

1 answer:

jeyben [28]3 years ago

6 0

31-1/4-2=

30/2=

slope=15

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A snail is 20 inches above the ground. It slips down 6 inches and then creeps up 12 inches. What is the snail's height now?

bixtya [17]

Answer:

Step-by-step explanation:

20 inches minus 6 inches plus 12

20-6=14

14+12= 26

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3 years ago

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Find the value of x and y in the parallelogram below

avanturin [10]

Answer:

y = 41

x = 64

Step-by-step explanation:

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3 years ago

4. If f(x) = 5X + 8, g(x) = 7X -2 Find (f - g)(x)

Licemer1 [7]

Answer:

-2x+10

Step-by-step explanation:

f(x)=5x+8

g(x)=7x-2

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3 years ago

If A=(0,0) and B=(8,2), what is the length of AB

NeX [460]

Answer:

$\boxed{\sf Distance_{AB}= 8.24 \ units }$

Step-by-step explanation:

Here two points are given to us and we need to find the distance between the two points . The given points are , A(0,0) and B(8,2) . The distance between the two points can be found out using the Distance Formula , which is ,

Distance Formula:-

$\sf\implies \green{ Distance =\sqrt{ (x_2-x_1)^2+(y_2-y_1)^2}}$

Therefore on substituting the respective values ,we can find the Distance as ,

$\sf\longrightarrow Distance = \sqrt{ ( 0 - 8)^2 + (0-2)^2}$

Simplify the brackets ,

$\sf\longrightarrow Distance =\sqrt{ (-8)^2+(-2)^2}$

Square the numbers inside the squareroot ,

$\sf\longrightarrow Distance =\sqrt{ 64 + 4}$

Add the numbers inside the squareroot ,

$\sf\longrightarrow Distance = \sqrt{68}$

Find the value of squareroot,

$\sf\longrightarrow \boxed{\blue{\sf Distance = 8.24 \ units }}$

Hence the distance between the two points is 8.24 units .

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3 years ago

Starting at sea level, a submarine descends at a rate of 65 meters per minute. Relative to sea level, where is the submarine 10

Stolb23 [73]

Answer:

Step-by-step explanation:

It's awfully deep.

1 minute = 65 meters

10 minutes = 10 * 65 = 650 meters below sea level.

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3 years ago