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grigory [225]
3 years ago
12

Convert 14 ft in yd and ft

Mathematics
1 answer:
almond37 [142]3 years ago
3 0

multiply 3 by 14 it equals 42...

hope this helpes...

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One point on the trend line is 200,6 using this point and the y-intercept find the slope of the trend line.
Marina CMI [18]

Step-by-step explanation:

Use the formula (Y2 - Y1)/(X2 - X1) to find the slope between two points

We'll make Point 1 (which is X1 and Y1) the Y-intercept so

X1, Y1 = (0, 5.00)

And we'll make Point 2 (which is X2 and Y2) the point on the trend line

X2, Y2 = (200, 6.00)

Plug into the formula:

(6.00 - 5.00)/(200 - 0)

= 1/200 or 0.005

Slope: 1/200 or 0.005

---

If this helps, please mark as Brainliest! :)

6 0
3 years ago
rebekah's baby brother weighs 7.71 pounds.How much will her baby brother weigh if he gains 1.3 pounds each week for two weeks?
NemiM [27]

Answer:

10.31 pounds

Step-by-step explanation:

First, we multiply 1.3 x 2 because he is gaining 1.3 for the next TWO weeks.

1.3 x 2 = 2.6

Now, add 7.71 + 2.6 because that is the weight he started with.

7.71 + 2.6 = 10.31‬

Her brother will weight 10.31 pounds if he is 7.71 lbs and continues to gain 1.3 pounds each week for two weeks.

8 0
3 years ago
Use the normal distribution of SAT critical reading scores for which the mean is 502 and the standard deviation is 116. Assume t
PSYCHO15rus [73]

Answer:

(a) 93.19%

(b) 267.3

Step-by-step explanation:

The population mean and standard deviation are given as 502 and 116 respectively.

Consider, <em>X</em> be the random variable that shows the SAT critical reading score is normally distributed.

(a) The percent of the SAT verbal scores are less than 675 can be calculated as:

P(X

Thus, the required percentage is 93.19%

(b)

The number of SAT verbal scores that are expected to be greater than 575 can be calculated as:

P(X>575)=P(\frac{x-502}{116}>\frac{575-502}{116}\\P(X>575)=P(Z>\frac{575-502}{116})\\P(X>575)=P(Z>0.6293)\\P(X>575)=0.2673

So,

Out of 1000 randomly selected SAT verbal scores, 1000(0.2673) = 267.3 are expected to have greater than 575.

8 0
3 years ago
Pliz answer this question
irina1246 [14]
Cent is by the hundred so one percent is 1/100 so .6%=6/1000
which can be reduced to 3/500
7 0
3 years ago
Listed below are amounts​ (in millions of​ dollars) collected from parking meters by a security service company and other compan
Vikentia [17]

Answer:

CV=\frac{0.1252}{1.57}=0.07975

CV=\frac{0.1317}{1.72}=0.07657

The relative variability is almost equal in both samples a slight greater variability can be noticed in the first sample.

Step-by-step explanation:

The coefficient of variation of a sample is defined as the ratio between the mean standard deviation and the sample mean. And it represents the percentage relation of the variation of the data with respect to the average.

CV=\frac{S}{\bar X}

In the case of the first sample you have:

CV=\frac{0.1252}{1.57}=0.07975

In the case of the second sample you have:

CV=\frac{0.1317}{1.72}=0.07657

The relative variability is almost equal in both samples a slight greater variability can be noticed in the first sample.

6 0
3 years ago
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