3 years ago

Help me out please an thank you

Mathematics

1 answer:

klio [65]3 years ago

5 0

Answer:

756.748

Step-by-step explanation:

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What is one tenth of 0.5

Paraphin [41]

0.5 x 1/10 = 0.05 All you do is multiply

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3 years ago

Todo numero es divisible por 3, si al sumar el total de sus digitos, se obtiene un numero mutiplo del tres (se puede expresar co

Free_Kalibri [48]

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si, eso es correcto

Step-by-step explanation:

Espero que esto ayude a marcar el MÁS CEREBRAL !!!

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Simplify (x − 4)(3x2 − 6x + 2). 3x3 + 6x2 − 22x + 8 3x3 − 18x2 + 26x − 8 3x3 − 18x2 − 22x − 8 3x3 + 6x2 + 22x + 8

kogti [31]

Answer:

3x^3-18x^2+26x-8

Step-by-step explanation:

(x-4)(3x^2-6x+2)

3x^3-6x^2+2x-12x^2+24x-8

3x^3-18x^2+26x-8

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3 years ago

Angles E and Fare in ration 2:5. If the sum of E+F=70, What are the

LenKa [72]

Answer:

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3 0

3 years ago

Read 2 more answers

There are eight students in a class. Only one of them has passed Exam P/1 and only one of them has passed Exam FM/2. No student

Svetach [21]

Answer: There is probability of 0.57 chances that exactly three students from a group of four students have not passed Exam P/1 or Exam FM/2.

Step-by-step explanation:

Total number of students = 8

Number of student who has passed Exam P/1 = 1

Number of student who has passed Exam FM/2 = 1

No student has passed more than one exam.

According to question, exactly three students from a randomly chose group of four students have not passed Exam P/1 or Exam FM/2.

So, Probability will be

$\frac{^6C_3\times ^2C_1}{^8C_4}\\\\=\frac{20\times 2}{70}\\\\=\frac{4}{7}\\\\=0.57$

Hence, there is probability of 0.57 chances that exactly three students from a group of four students have not passed Exam P/1 or Exam FM/2.

4 0

3 years ago